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Stels [109]
3 years ago
12

A radioactive substance decays exponentially: The mass at time t is m(t) = m(0)e^kt, where m(0) is the initial mass and k is a n

egative constant. The mean life M of an atom in the substance is
[infinity]
M = âk â« te^kt dt.
0

For the radioactive carbon isotope, 14C, used in radiocarbon dating, the value of k is -0.000121. Find the mean life of a 14C atom.
Mathematics
1 answer:
forsale [732]3 years ago
5 0

Answer:

mean life = 8264.5 s

Step-by-step explanation:

k = - 0.000121

The relation is given by

m = mo e^{kt}

Now, the mean life is the life time for which the sample retains.

The mean life is the reciprocal of the decay constant.  

The relation between the mean life and the decay constant is

\tau =\frac{1}{k}\\\\\tau = \frac{1}{0.000121} = 8264.5 seconds

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Step-by-step explanation:

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3 years ago
An auto dealership sells minivans and sedans. In January, they sold 10 minivans and 20 sedans. In February, they sold 7 minivans
zaharov [31]

Answer:

january = 10/20 = 1/2

februry = 7/14 = 1/2

so, we conclude that the auto dealership didn't have a lower ratio, since the ratio is equal in both months.

<em>hope it helps :)</em>

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3 years ago
What is the solution of the equation when solved using the quadratic formula?<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B
Artemon [7]

Answer:

x=\pm2i\sqrt{5}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Standard Form: ax² + bx + c = 0
  • Quadratic Formula: x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}

<u>Algebra II</u>

  • Imaginary Numbers: √-1  = i

Step-by-step explanation:

<u>Step 1: Define Equation</u>

x² + 20 = 0

<u>Step 2: Identify Variables</u>

a = 1

b = 0

c = 20

<u>Step 3: Find roots </u><em><u>x</u></em>

  1. Substitute:                    x=\frac{-0\pm\sqrt{0^2-4(1)(20)} }{2(1)}
  2. Exponents:                   x=\frac{-0\pm\sqrt{0-4(1)(20)} }{2(1)}
  3. Multiply:                        x=\frac{-0\pm\sqrt{0-80} }{2}
  4. Subtract:                       x=\frac{\pm\sqrt{-80} }{2}
  5. Factor:                          x=\frac{\pm\sqrt{-1} \sqrt{80} }{2}
  6. Simplify:                        x=\frac{\pm4i\sqrt{5} }{2}
  7. Divide:                          x=\pm2i\sqrt{5}
6 0
2 years ago
What is the equation of this graphed line?
o-na [289]

Answer:

y = 2x + 2

Step-by-step explanation:

Notice that this line passes thru (-4, -6) and (2, 6). As we move from (-4, -6) and (2, 6), x increases by 6 and y increases by 12.  Thus, the slope is

m = rise / run = 12/6 = 2.

From the graph we can see that the y-intercept is (0,2).  Thus, the slope-intercept equation of this line is:

y = 2x + 2

8 0
3 years ago
Read 2 more answers
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