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Basile [38]
2 years ago
10

Saving...

Mathematics
1 answer:
vesna_86 [32]2 years ago
8 0

Answer:

m\angle y=35.69^o

Step-by-step explanation:

The picture of the question in the attached figure

we know that

In the right triangle of the figure

sin(y)=\frac{7}{12} ----> by SOH (opposite side divided by the hypotenuse)

using a calculator

m\angle y=sin^{-1}(\frac{7}{12})=35.69^o

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PLS HELP ME
Anuta_ua [19.1K]

Interest on interest, or compound interest, is the adding of interest to the principal sum of a loan or deposit. Mike's account balance after 21 years is $69,131.44.

<h3>What is compound interest?</h3>

Interest on interest, or compound interest, is the adding of interest to the principal sum of a loan or deposit. It's the outcome of reinvesting interest rather than paying it out so that interest is received on the principal plus previously collected interest in the next quarter.,

A = P(1+ \dfrac{r}{n})^{nt}

where A is the final amount

P is the principal amount

r is the rate of interest

n is the number of times interest is charged in a year

t is the number of years

The principal amount that Mike invested is $29,000. The rate of interest is 7.24% compounded daily, for 21 years. Therefore, the account balance after 21 years is

\text{Account Balance after 21 years} = 29,000(1+\dfrac{0.0724}{365})^{(365 \times 21)}

                                                     = $69,131.44

Hence, Mike's account balance after 21 years is $69,131.44.

Learn more about Compound Interest:

brainly.com/question/25857212

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3 0
1 year ago
What is 5 divided by-6/5
klasskru [66]
-25/6. hope this helps!

6 0
3 years ago
A) Use the definition of Laplace transform to find L{f }. (Do the integrals.) For what values of s is L{f } defined?f(t) = (2t+1
kiruha [24]

For the given function f(t) = (2t + 1) using definition of Laplace transform the required solution is L(f(t))s = [ ( 2/s²) + ( 1/s) ].

As given in the question,

Given function is equal to :

f(t) = 2t + 1

Simplify the given function using definition of Laplace transform we have,

L(f(t))s = \int\limits^\infty_0 {f(t)e^{-st} } \, dt

          =  \int\limits^\infty_0[2t +1] e^{-st} dt

          = 2\int\limits^\infty_0 te^{-st} + \int\limits^\infty_0e^{-st} dt

         = 2 L(t) + L(1)

L(1) = \int\limits^\infty_0e^{-st} dt

     = (-1/s) ( 0 -1 )

     = 1/s , ( s >  0)

2L ( t ) = 2\int\limits^\infty_0 te^{-st}

        =  2[t\int\limits^\infty_0 e^{-st} - \int\limits^\infty_0 ({(d/dt)(t) \int\limits^\infty_0e^{-st} \, dt )dt]

        =  2/ s²

Now ,

L(f(t))s = 2 L(t) + L(1)

          = 2/ s² + 1/s

Therefore, the solution of the given function using Laplace transform the required solution is L(f(t))s = [ ( 2/s²) + ( 1/s) ].

Learn more about Laplace transform here

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8 0
10 months ago
2.5(4k+2)=12k solve for k
finlep [7]

Answer:

k = 2.5

Step-by-step explanation:

2.5 (4k+2) = 12k

10k + 5 = 12k

-10k

5 = 2k

5/2

2.5

3 0
3 years ago
Read 2 more answers
Y=1/2x +5<br> Y=-3/2x-7<br> Find x and y
gayaneshka [121]
I'm going to use the substitution method. 

If y = - 3/2 - 7, then:

1/2x + 5 = - 3/2x - 7

Combine like terms: 

4/2x = - 12. Mutiply both sides by 2/4 to get x = -12 (2/4)

Simplify to get:

x = - 6.

Plug - 6 back in for x in either equation.

Y = 1/2( - 6) + 5 which becomes Y = - 3 + 5.

X = - 6, Y = 2





8 0
3 years ago
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