<u>Answer:</u>
<em> needed to heat the amount of water giving.
</em>
<u>Explanation:</u>
To solve this question we first need to know the specific heat of water which is given by <em>4.18 joules</em> Per gram for increasing <em>1° of temperature</em>. Now since one gram of water name one joules per gram so 2 grams will need <em>twice of 4.18</em> that is 8.36 similarly 50 grams will need
Now we need to calculate the heat for 10° of change because temperature rises from 50° centigrade to 60° centigrade and difference in degrees
<em>so heat needed is= </em>
Answer:
running helps my heart beat
Explanation:
Structural formula of propene
molecular formula = C₃H₆
molecular mass = 12×3+1×6 = 36+6 = 42
no. of double bond = 1
I think the ice is warmed from 10 degrees Fahrenheit to 32 degrees Fahrenheit. The ice then melts (I believe 333kj/kg K) and then it warms up to 305 K. For that this occurs the heat capacity of the water is 4.19 kj/kg K.<span>
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When you are dealing with mole calculations, whatever you do to one side of the equation you must also do to the other. .5Fe is 1/8th of 4Fe, so in order to determine what it will yield you must divide the given amount of Fe2O3 and divide THAT by 1/8th, leaving you with .25 mol of Fe2O3.