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Igoryamba
3 years ago
7

Material A has a small latent heat of fusion. Material B has a large heat of fusion. Which of the following statements is true?

(assume equal masses of both materials) material A will take less energy to phase change to a liquid material A will take more energy to phase change to a liquid material A will take less energy to phase change to a gas material A will take more energy to phase change to a gas
Chemistry
2 answers:
neonofarm [45]3 years ago
8 0

Answer: Material A will take less energy to phase change to a liquid material.

Explanation:

The energy provided to change the enthalpy of a substance is known as latent heat of fusion. This energy actually helps in changing the state of a substance that is from solid to liquid or vice versa.

Hence, a substance with small latent heat of fusion will require less energy to change its phase. Whereas a substance with large heat of fusion will require large energy to change its phase.

There, it can be concluded that material A will take less energy to phase change to a liquid material

Olin [163]3 years ago
7 0
The correct answer would be the first option. Material A having a smaller latent heat of fusion would mean that it will take only less energy to phase change into the liquid phase. Latent of heat of fusion is the amount of energy needed of a substance to phase change from solid to liquid or liquid to solid.
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6 0
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When fluorine gas combines with water vapor, the following reactions occurs.
jonny [76]
Hello!

The Chemical reaction is the following:

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If we assume that all the gases are ideal gases, we can describe the coefficients of this reaction as Volume rather than moles, so we can apply the following equations:

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Have a nice day!

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As an athlete exercises, sweat is produced and evaporated to help maintain a proper body temperature. On average, an athlete los
dmitriy555 [2]

<u>Answer:</u> For the given amount of sweat lost, the amount of energy required will be 692,899 Joules.

<u>Explanation:</u>

We are given:

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Amount of sweat lost = 307 grams

Applying unitary method:

For 1 g of sweat lost, the energy required is 2257 Joules

So, for 307 grams of sweat lost, the energy required will be = \frac{2257J}{1g}\times 307g=692,899J

Hence, for the given amount of sweat lost, the amount of energy required will be 692,899 Joules.

7 0
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