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k0ka [10]
4 years ago
11

Which of the elements below has the greatest electronegativity? He F Fr Rn

Chemistry
2 answers:
Studentka2010 [4]4 years ago
8 0

Answer: The element having greatest electronegativity is Fluorine.

Explanation:

Electronegativity is defined as the tendency of an element to attract electrons towards itself. More strongly an element attracts electrons, more will be its electronegativity and vice-versa.

Electronegativity of Group 18 elements is usually 0 except Xenon which has an electronegativity value of 2.6. These elements have filled valence shell and hence they do not attract electrons towards itself and hence, has no electronegativity.

In a periodic table, electronegativity decreases down the group and increases from left to right in a period.

Fluorine is present at Period 2, Group 17 of the periodic table.

Francium is present at Period 7, Group 1 of the periodic table.

Hence, fluorine will have the greatest value of electronegativity among the given elements.

Law Incorporation [45]4 years ago
3 0

F.
it's the greatest electron "hogger"
as you get closet to it, the stronger the electro negitivity.
He is halogen : they don't like to gain electrons. they are already stable.

Fr and Rn
are metals as far is I can remember. they would prefer losing electrons.
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The molarity of the solutions are as follows:

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  • solution F and D will have the same molarity
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<h3>What is molarity of a solution?</h3>

The molarity of a solution is the amount in moles of a substance present in a given volume of solution.

From the image of the solution given:

  • solution B has the highest molarity
  • solutions A, D and F have the same molarity
  • when solutions A and C are mixed, the resulting solution have a lower molarity than B
  • solution F and D will have the same molarity after 75 mL and 50 mL of water are added to each respectively
  • the molarity of B is 12/50 = 4/16.7. Volume of water required to be evaporated = 25 - 16.7 = 8.3 mL

Therefore, the molarity of the solutions depends on the moles of substance present per given volume of solution.

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2 years ago
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3 years ago
20 ml each of oxygen and methane are allowed to react when the reaction is completed.  The system now contains
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Answer:

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How many particles are in a 151 g sample of Li2O?
neonofarm [45]

Answer:

3.052 × 10^24 particles

Explanation:

To get the number of particles (nA) in a substance, we multiply the number of moles of the substance by Avogadro's number (6.02 × 10^23)

The mass of Li2O given in this question is as follows: 151grams.

To convert this mass value to moles, we use;

moles = mass/molar mass

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= 30.52 × 10^23

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