These minutes are further divided into sixty parts called seconds. The words minute and second used in this context have no immediate connection to how those words are usually used as amounts of time. In a full circle there are 360 degrees. Each degree is split up into 60 parts, each part being 1/60 of a degree.
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Answer:
13.1 L
Explanation:
Using the combined gas law:
P1V1/T1 = P2V2/T2
Where;
P1 = initial pressure (atm)
P2 = final pressure (atm)
V1 = initial volume (L)
V2 = final volume (L)
T1 = initial temperature (K)
T2 = final temperature (K)
Based on the information provided in this question;
P1 = 1.95 atm
P2 = 0.65 atm
V1 = 5.0 L
V2 = ?
T1 = 20 °C = 20 + 273 = 293K
T2 = -15 °C = -15 + 273 = 258K
Using P1V1/T1 = P2V2/T2
1.95 × 5/293 = 0.65 × V2/258
9.75/293 = 0.65V2/258
0.0333 = 0.00252V2
V2 = 0.0333 ÷ 0.00252
V2 = 13.1 L
Answer:
Butan-1-ol or Butanol
2-methylpropan-2-ol
2-methylpropan-1-ol
Butan-2-ol
Explanation:
Data Give:
Three Isomers are given
names of These =?
Details:
Isomers:
Isomers are those chemical compounds that have same molecular formula but different structures.
In the given question the compound have same molecular formula that is C₄H₉OH but the structures are different.
So due to different structures they are named differently.
The 1st and last one are straight Chains and the other 2 are branched. all the structure have four carbon atoms, one OH group and 9 hydrogen atoms.
Names are given in attachment
butan-1-ol or Butanol
As it contain 4 carbon atoms an -OH group is attached at position 1.
________________
2-methylpropan-2-ol
In this -OH and -CH₃ is attached on carbon 2
_____________
2-methylpropan-1-ol
In this -CH₃ attached at position 2 and -OH is attached on Carbon 1.
______________
Butan-2-ol
In this 4 carbons are in straight chain and a -OH group is attached on position 2 of carbon
Answer:
53j/k
Explanation:
ΔH = TΔS => ΔS = ΔH/T = 1.5 x 10⁴ joules/283 Kelvin = 53 joules/K