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GalinKa [24]
3 years ago
13

A project has a 50% chance of doubling your investment in 1 year and a 50% chance of losing half your money. what is the expecte

d return on this investment project? what is the standard deviation of returns?
Mathematics
1 answer:
ra1l [238]3 years ago
5 0
Let X be the random variable. 
We have:
P(X=2x)=\dfrac{1}{2}
P(X=\dfrac{x}{2})=\dfrac{1}{2}
Compute the mean like this:
2x\times \frac{1}{2}+ \frac{x}{2}\times \frac{1}{2}= \frac{5}{4}x
It is the expected return. 
First compute the following: E(X)^2= \frac{25}{16}x^2
Then E(X^2)=(2x)^2\times \frac{1}{2}+ (\frac{x}{2})^2\times \frac{1}{2}= \frac{17}{8}x^2
Finally the standard deviation:
\sqrt{\frac{17}{8}x^2- \frac{25}{16}x^2}=  \frac{3}{4}x
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A catapult launches a boulder with an upward velocity of 120 ft/s. The height of the boulder, h,
Vlad1618 [11]

Answer:

Reaches a maximum height of 235.00 feet in 3.75 seconds.

Step-by-step explanation:

The height of the boulder, h,  in feet after t seconds is given by the function is given by :

h=-16t^2+120t+10 .....(1)

For maximum height, put \dfrac{dh}{dt}=0

i.e.

\dfrac{d(-16t^2+120t+10)}{dt}=0\\\\-32t+120=0\\\\32t=120\\\\t=3.75\ s

Put t = 3.75 in equation (1). So,

h=-16(3.75)^2+120(3.75)+10\\\\h=235\ \text{feet}

So, the boulder's maximum height is 235 feets and it takes 3.75 s to reach to its maximum height.

3 0
3 years ago
chris buys p pairs of pants and 4 more shirts than pairs of pants. Shirts cost $18 each and pair of pants cost $25 each. What do
jasenka [17]

p is the number of pants

25 is $25 for the pants

18 is $18 for the pants

4 represents that you bought 4 more shirts than pants

plz rate as brainliest answer

6 0
3 years ago
Which set of sides will make a triangle
ElenaW [278]

Answer:

the third one 10 cm, 9cm 9cm

6 0
3 years ago
Which of the expressions below are equivalent? 8x - 4 4x 4(2x - 1)
alexandr402 [8]
8x-4 and 4(2x-1)




4(2x-1) the four needs to be distributed in the parentheses.

4*2x=8x
4*(-1)=(-4)

8x-4=8x-4
4 0
3 years ago
How do you do this problem?
zhenek [66]

Answer:

A) g is increasing, and the graph of g is concave up.

Step-by-step explanation:

g'(x) = ∫₀ˣ e^(-t³) dt

Since e^(-t³) is always positive, ∫₀ˣ e^(-t³) dt is positive when x > 0.  So the function is increasing.

Find g"(x) by taking the derivative using second fundamental theorem of calculus:

g"(x) = e^(-x³)

g"(x) is always positive, so the function is always concave up.

5 0
3 years ago
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