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GalinKa [24]
3 years ago
13

A project has a 50% chance of doubling your investment in 1 year and a 50% chance of losing half your money. what is the expecte

d return on this investment project? what is the standard deviation of returns?
Mathematics
1 answer:
ra1l [238]3 years ago
5 0
Let X be the random variable. 
We have:
P(X=2x)=\dfrac{1}{2}
P(X=\dfrac{x}{2})=\dfrac{1}{2}
Compute the mean like this:
2x\times \frac{1}{2}+ \frac{x}{2}\times \frac{1}{2}= \frac{5}{4}x
It is the expected return. 
First compute the following: E(X)^2= \frac{25}{16}x^2
Then E(X^2)=(2x)^2\times \frac{1}{2}+ (\frac{x}{2})^2\times \frac{1}{2}= \frac{17}{8}x^2
Finally the standard deviation:
\sqrt{\frac{17}{8}x^2- \frac{25}{16}x^2}=  \frac{3}{4}x
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3y''-6y'+6y=e*x sexcx
Simora [160]
From the homogeneous part of the ODE, we can get two fundamental solutions. The characteristic equation is

3r^2-6r+6=0\iff r^2-2r+2=0

which has roots at r=1\pm i. This admits the two fundamental solutions

y_1=e^x\cos x
y_2=e^x\sin x

The particular solution is easiest to obtain via variation of parameters. We're looking for a solution of the form

y_p=u_1y_1+u_2y_2

where

u_1=-\displaystyle\frac13\int\frac{y_2e^x\sec x}{W(y_1,y_2)}\,\mathrm dx
u_2=\displaystyle\frac13\int\frac{y_1e^x\sec x}{W(y_1,y_2)}\,\mathrm dx

and W(y_1,y_2) is the Wronskian of the fundamental solutions. We have

W(e^x\cos x,e^x\sin x)=\begin{vmatrix}e^x\cos x&e^x\sin x\\e^x(\cos x-\sin x)&e^x(\cos x+\sin x)\end{vmatrix}=e^{2x}

and so

u_1=-\displaystyle\frac13\int\frac{e^{2x}\sin x\sec x}{e^{2x}}\,\mathrm dx=-\int\tan x\,\mathrm dx
u_1=\dfrac13\ln|\cos x|

u_2=\displaystyle\frac13\int\frac{e^{2x}\cos x\sec x}{e^{2x}}\,\mathrm dx=\int\mathrm dx
u_2=\dfrac13x

Therefore the particular solution is

y_p=\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x

so that the general solution to the ODE is

y=C_1e^x\cos x+C_2e^x\sin x+\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x
7 0
3 years ago
What is 12a equal to if 4a plus 6b = 10 and 2a-4b=12?
hram777 [196]
12a=x
4a+6b=10
2a+3b=5
2a-4b=12
a-2b=6
2a+3b+1=a-2b
a+5b+1=0
a=-1-5b

2(-1-5b)+3b=5
-2-10b+3b=5
-2-7b=5
-7b=7
7b=-7
b=-1

-1-5*-1=a
-1+5=a
4=a

4*12=48
12a=48

Hope this helps :)
3 0
3 years ago
Read 2 more answers
How would the graph of the relation y=3x-2 change if the 3 and -2 were both doubled? 
Lena [83]
<u>y = 3x - 2</u>

-- The ' 3 ' is the slope. If you double it to ' 6 ', the line is steeper.

-- The ' -2 ' is the y-intercept. If you double it to ' -4 ', the line crosses the y-axis lower.

Choice <u>(a)</u> says that . . . "... steeper, and lower y-intercept".

6 0
3 years ago
X<br> I ㅗ<br> ]<br> Factor: -2/3<br> out of -3X<br> - 12
sesenic [268]

Answer:what is this

Step-by-step explanation:

bruh

3 0
2 years ago
Tom was driving 20.3 meters per second in a 45 mile per hour zone. Was Tom speeding? Explain using a unit conversion as well as
My name is Ann [436]

Answer:

Tom was speeding.

Step-by-step explanation:

The driving speed of Tom = 20.3 meters per second.

Speed allowed in the zone = 45 miles per hour zone.

Since the unit of speed allowed is given in miles per hour but the speed of tom is given in meters per second. So, first, we have to convert the meter per second into mile per hour then we can compare and find that Tom is speeding or not.  

1 mile = 1609.34 meters

1 hour = 3600 second

Now convert 20.3 into mile per hour.

20.3 meters per second. = (20.3 / 1609.34)*3600 = 45.40981 mile per hour.

Since Tom’s speed is more than the allowed speed so he is speeding.

7 0
3 years ago
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