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dalvyx [7]
3 years ago
15

Gas particles are pumped into a rigid steel container at a constant temperature. Which statement describes the change in pressur

e that would occur inside the steel container. (pic)​

Chemistry
1 answer:
Masteriza [31]3 years ago
8 0

Answer:

The pressure inside the container would increase with each additional pump.

Explanation:

  • From the general gas law of ideal gases:

<em>PV = nRT,</em>

where, P is the pressure of the gas.

V is the volume of the gas.

n is the no. of moles of the gas.

R is the general gas constant.

T is the temperature of the gas.

  • As clear from the gas law; the pressure of the gas is directly proportional to the no. of moles of the gas.

<em>P α n.</em>

  • As gas particles are pumped into a rigid steel container, the no. of moles of the gas will increase.

So, the pressure of the gas will increase.

<em>Thus, the right choice is: The pressure inside the container would increase with each additional pump.</em>

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8 0
3 years ago
If a reaction occurs, what will be the products of the unbalanced reaction below?
castortr0y [4]

Explanation:

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8 0
3 years ago
The products in a decomposition reaction _____. are compounds can be elements or compounds are elements include an element and a
ivann1987 [24]

Answer:

compounds are elements include an element and a compound

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7 0
2 years ago
To a 25.00 mL volumetric flask, a lab technician adds a 0.150 g sample of a weak monoprotic acid, HA , and dilutes to the mark w
Elis [28]

<u>Answer:</u> The number of moles of weak acid is 4.24\times 10^{-3} moles.

<u>Explanation:</u>

To calculate the moles of KOH, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}\text{Volume of solution (in L)}}

We are given:

Volume of solution = 43.81 mL = 0.04381 L      (Conversion factor: 1L = 1000 mL)

Molarity of the solution = 0.0969 moles/ L

Putting values in above equation, we get:

0.0969mol/L=\frac{\text{Moles of KOH}}{0.04381}\\\\\text{Moles of KOH}=4.24\times 10^{-3}mol

The chemical reaction of weak monoprotic acid and KOH follows the equation:

HA+KOH\rightarrow KA+H_2O

By Stoichiometry of the reaction:

1 mole of KOH reacts with 1 mole of weak monoprotic acid.

So, 4.24\times 10^{-3}mol of KOH will react with = \frac{1}{1}\times 4.24\times 10^{-3}=4.24\times 10^{-3}mol of weak monoprotic acid.

Hence, the number of moles of weak acid is 4.24\times 10^{-3} moles.

6 0
3 years ago
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