Question

Balance the following reaction in KOH (under basic conditions). What are the coefficients in for C3H8O2 and KMnO4 in the balanced reaction? C3H8O2(aq) + KMnO4(aq) → C3H2O4K2(aq) + MnO2(aq)

Answer 1

Answer:

Coefficient of $C_3H_8O_2=3$

Coefficient of $KMnO_4$=8

Explanation:

We are given that  a reaction in which $C_3H_8O_2$ reacts with $KMnO_4$

We have to find the coefficient of each reactants in balanced reaction

$3C_3H_8O_2(aq)+8KMnO_4(aq)\rightarrow 3C_3H_2O_4K_2(aq)+8MnO_2(aq)+2KOH+8H_2O$

Coefficient is defined the constant  value multiplied with a reactant in a reaction.

Coefficient of $C_3H_8O_2$=3

Coefficient of $KMnO_4=8$

Coefficient of $C_3H_2O_4K_2=3$

Coefficient of $MnO_2=8$

Coefficient of $H_2O=8$

Coefficient of KOH=2

Hence, Coefficient of $C_3H_8O_2=3$ and coefficient of $KMnO_4=8$