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Ivan
4 years ago
13

Balance the following reaction in KOH (under basic conditions). What are the coefficients in for C3H8O2 and KMnO4 in the balance

d reaction? C3H8O2(aq) + KMnO4(aq) → C3H2O4K2(aq) + MnO2(aq)
Chemistry
1 answer:
GrogVix [38]4 years ago
7 0

Answer:

Coefficient of C_3H_8O_2=3

Coefficient of KMnO_4=8

Explanation:

We are given that  a reaction in which C_3H_8O_2 reacts with KMnO_4

We have to find the coefficient of each reactants in balanced reaction

3C_3H_8O_2(aq)+8KMnO_4(aq)\rightarrow 3C_3H_2O_4K_2(aq)+8MnO_2(aq)+2KOH+8H_2O

Coefficient is defined the constant  value multiplied with a reactant in a reaction.

Coefficient of C_3H_8O_2=3

Coefficient of KMnO_4=8

Coefficient of C_3H_2O_4K_2=3

Coefficient of MnO_2=8

Coefficient of H_2O=8

Coefficient of KOH=2

Hence, Coefficient of C_3H_8O_2=3 and coefficient of KMnO_4=8

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