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Taya2010 [7]
3 years ago
9

For production of crude biodiesel from 250,000 kg/h rapeseed oil reacted with 75,000 kg/h ethanol and 250 kg/h potassium hydroxi

de with 1 h residence time in a the continuous transesterification process, determine the production yield in kg biodiesel/h assuming 95% conversion of oil.
Chemistry
1 answer:
Tanya [424]3 years ago
7 0

Answer:

will be 237,500 kg/h

Explanation:

The necessary ingredients to produce the biodiesel from the plant are: the plant, ethanol and the base. So after a period of 1 hour, the biodiesel that is going to be formed is 237, 500 kg/h.

Just apply the rule of three to the main source of biodiesel, that in this case is the rapessed plant and apply the 95 %. Ex:

Biodiesel = 0.95 x 250,000 = 237,500 kg/h

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Given the equation Ca + H2O --&gt; Ca(OH)2 + H2 how many grams of calcium will react completely with 10.0 grams of water? *
Yuki888 [10]

Answer: 11.0 g of calcium will react with 10.0 grams of water.

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To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

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3 years ago
The volume of a gas at 7.00°c is 49.0 ml. if the volume increases to 74.0 ml and the pressure is constant, what will the tempera
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