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Taya2010 [7]
3 years ago
9

For production of crude biodiesel from 250,000 kg/h rapeseed oil reacted with 75,000 kg/h ethanol and 250 kg/h potassium hydroxi

de with 1 h residence time in a the continuous transesterification process, determine the production yield in kg biodiesel/h assuming 95% conversion of oil.
Chemistry
1 answer:
Tanya [424]3 years ago
7 0

Answer:

will be 237,500 kg/h

Explanation:

The necessary ingredients to produce the biodiesel from the plant are: the plant, ethanol and the base. So after a period of 1 hour, the biodiesel that is going to be formed is 237, 500 kg/h.

Just apply the rule of three to the main source of biodiesel, that in this case is the rapessed plant and apply the 95 %. Ex:

Biodiesel = 0.95 x 250,000 = 237,500 kg/h

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Answer:

Potassium is more reactive than aluminium, so no reaction takes place. But aluminium is more reactive than copper, so it replaces the copper in copper nitrate

<h3>Explanation:</h3>

More reactive metal compound + less reactive metal

-> no reaction

However

Less reactive metal compound + more reactive metal

-> more reactive metal compound + less reactive metal

This is called substitution reaction where the more reactive metal replaces the less reactive metal in the compound.

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HCl + Ca(OH)2 = CaCl2 + H2O - Chemical Equation Balancer.

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2 years ago
Determain the number of moles in 2.24l of ch4 at stp
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From the question given above, the following data were obtained:

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