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ch4aika [34]
3 years ago
5

Take the regular compass and hold it so the case is vertical. Now use it to investigate the direction of the coil’s magnetic fie

ld at locations other than the central axis. What happens as you move away from the center axis toward the coil? What happens above the coil? Outside the coil? Below the coil?
Physics
1 answer:
Sliva [168]3 years ago
3 0

Answer:

Please find the answer in the explanation

Explanation:

Take the regular compass and hold it so the case is vertical. Now use it to investigate the direction of the coil’s magnetic field at locations other than the central axis.

What happens as you move away from the center axis toward the coil? The direction of the magnetic compass needle will move in an opposite direction since the direction of the induced voltage is reversed.

What happens above the coil?

the needle on the magnetic compass will be deflected. Since compasses work by pointing along magnetic field lines

Outside the coil? The magnetic compass needle will experience no deflection. Since there is no induced voltage or current.

Below the coil?

The needle will move in an opposite direction.

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physics major is cooking breakfast when he notices that the frictional force between the steel spatula and the Dry Steel frying
givi [52]

Answer:0.667 N

Explanation:

Given

It is noticed that Frictional Force is 0.2 N

Coefficient of kinetic Friction \mu _k=0.3

We know Friction Force is given by

f_r=\mu _k\times Normal\ reaction

therefore

0.2=\mu _k\times N

0.2=0.3\cdot N

N=\frac{0.2}{0.3}

N=0.667 N

8 0
3 years ago
A stereo speaker is placed between two observers who are 40 m apart, along the line connecting them. if one observer records an
Nadya [2.5K]

The distance from observer A of intensity of sound 59 db is 28.64 m and the distance from observer B of intensity of sound 83 db is 11.36m

Explanation:

Let's solve this problem in parts

let's start by finding the intensity of the sound in each observer

observer A β = 59 db

            β = 10 log\frac{I_a}{I_o}

where I₀ = 1 \times 10^{-12}  W / m²

             I_a = I_b \times 10 ^{ \frac{\beta}{10} }

             I_a = 1\times 10 ^{-12} \times 10 ^{ \frac{59}{10} }

             I_a = 2.51 \times 10 ^{-6} W / m²

Similarly for Observer b I_b = 3.16 \times 10 ^ {-4}

now we use that the emitted power that is constant is the intensity over the area of ​​the sphere where the sound is distributed

P = I A

therefore for the two observers

the area of ​​a sphere is

A= 4\pi \times r^2

we substitute the above formula, we get

Let us call the distance from the observer A be to stereo speaker = x, so the distance from the observer B to the stereo speaker = 40- x; we substitute

            I_a (35 -x) ^2 = I_b x^2

after solving the above equation we get  x = 28.64 m

This is the distance of observer A

similarly The distance from observer B is 35 - x

= 40 - 28.64

= 11.36m

To know more about intensity of sound with the given link

#SPJ4

6 0
1 year ago
Explain the relationship between the distance between the string and your elbow and the effort required to lift the mass.
MissTica

Answer:

Sorry I I’m a little lost

Explanation:

5 0
3 years ago
Read 2 more answers
A(n ______ is a well-blended mixture that appears to be a single substance
Natali [406]

None of the choices is a suitable fill-in for the blank.

The question is fishing for "solution", but that makes
the statement false and misleading.

Salad dressing is a well-blended mixture. 
Blood is a well-blended mixture. 
Milk is a well-blended mixture. 
Petroleum is a well-blended mixture. 
None of these substances is a solution. 
A solution is not a well-blended mixture.

8 0
3 years ago
A rope pulls a 20 kg box up. If the tension in the rope is 275 N, what is the acceleration of the box?
Nana76 [90]

Answer:

<h3>The answer is 13.75 m/s²</h3>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question we have

a =  \frac{275}{20}  =  \frac{55}{4}  \\

We have the final answer as

<h3>13.75 m/s²</h3>

Hope this helps you

4 0
3 years ago
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