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Bezzdna [24]
3 years ago
7

What happens when light enters a pair of glasses

Physics
1 answer:
alexdok [17]3 years ago
6 0

Answer:

It refracts when it hits the glass.

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An electric generator has an 18-cmcm-diameter, 120-turn coil that rotates at 60 HzHz in a uniform magnetic field that is perpend
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Explanation:

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If a train is 100 kilometers away, how much sooner would you hear the train coming by listening to the rails (iron) as opposed t
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From tables, the speed of sound at 0°C is approximately
V₁ = 331 m/s (in air)
V₃ = 5130 m/s (in iron)

Distance traveled is
d = 100 km = 10⁵ m

Time required to travel in air is
t₁ = d/V₁ = 10⁵/331 = 302.12 s

Time required to travel in iron is
t₂ = d/V₂ = 10⁵/5130 = 19.49 s

The difference in time is
302.12 - 19.49 = 282.63 s

Answer:  283 s (nearest second)



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2 years ago
During World War II, mass spectrometers were used to separate the radioactive uranium isotope U-235 from its far more common iso
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21.55 m

Explanation:

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3 years ago
Can someone give me tips to passing AP Physics 1 with a solid A? Like, tips on how to memorize a lot of equations? Thank you!
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3 0
3 years ago
180 cm3 of hot tea at 97 °C are poured into a very thin paper cup with 20 g of crushed ice at 0 °C. Calculate the final temperat
Zolol [24]

Answer : The final temperature of the mixture is 91.9^oC

Explanation :

First we have to calculate the mass of water.

Mass = Density × Volume

Density of water = 1.00 g/mL

Mass = 1.00 g/mL × 180 cm³ = 180 g

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of hot water (liquid) = 4.18J/g^oC

c_2 = specific heat of ice (solid)= 2.10J/g^oC

m_1 = mass of hot water = 180 g

m_2 = mass of ice = 20 g

T_f = final temperature of mixture = ?

T_1 = initial temperature of hot water = 97^oC

T_2 = initial temperature of ice = 0^oC

Now put all the given values in the above formula, we get

(180g)\times (4.18J/g^oC)\times (T_f-97)^oC=-(20g)\times 2.10J/g^oC\times (T_f-0)^oC

T_f=91.9^oC

Therefore, the final temperature of the mixture is 91.9^oC

8 0
3 years ago
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