Three liquids that will not mix are poured into a cylindrical container. The volumes and densities of the liquids are 0.50 L, 2.
1 answer:
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The heat required to convert the unknown substance X from one phase to another is 1600 J times the specific heat of that substance.
Explanation:
The heat energy required to convert a substance or to heat up or increase the temperature of a substance can be obtained from the specific heat formula.
As per this formula, the heat energy applied should be equal to the product of mass of the substance with temperature gradient and also with specific heat of the substance. Basically, the heat provided to increase or convert a substance should be more than the specific heat of the substance.
Since, here the mass of the substance X is given as m = 20g and the temperature change is given from -10°C to 70°C.
Then ΔT = (70-(-10))=70+10=80°C.
As the substance is unknown, the specific heat of that substance can also not be determined. Hence keep it as C.
Q = 1600C J
Thus, the heat required to convert the unknown substance X from one phase to another is 1600 J times the specific heat of that substance.
Answer:
The value of heat transfer during the process Q = - 29.49 KJ
Explanation:
Given data
= 50
= 344.7 k pa
= 0.113
F = 366.4 K
= 477.6 K
Poly tropic index n = 1.2
gas constant for oxygen = 0.26
From ideal gas equation
= m R
Put all the values in above equation we get
⇒ 344.7 × 0.113 = m × 0.26 × 366.4
⇒ m = 0.408 kg
Heat transfer in poly tropic process is given by
Q =
Put all the values in above formula we get
⇒ Q =
⇒ Q = 2.5 × 0.408 × 0.26 × ( 366.4 - 477.6 )
⇒ Q = - 29.49 KJ
This is the value of heat transfer during the process & negative sign shows that heat is lost during the process.