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Viefleur [7K]
3 years ago
15

What is 1+ 1 cccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc

Mathematics
2 answers:
marysya [2.9K]3 years ago
3 0

Answer:

1+1 = 2

Step-by-step explanation:

Maurinko [17]3 years ago
3 0
1 + 1 = 2


0.5 + 0.4 + 0.7 + (-0.8) + 0.12 = 2
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What is y + 20 < 180? please help me
taurus [48]

Answer:

y < 160

Step-by-step explanation:

y + 20 < 180

    -20 < -20

y < 160

y is less than 160

5 0
2 years ago
Read 2 more answers
Peyton received a graduation gift from his grandparents of $12,700. He
arlik [135]

Answer:

Peyton's account will have $13,842.18 after a year.

Step-by-step explanation:

Given that Peyton received $ 12,700 and decided to invest it for a year in an account that grants an interest of 8.8% per year, compounded semiannually, to determine the amount of money that will be in said account after the passage of one year, it is necessary to perform the following calculation:

X = 12,700 (1 + 0.088 / 2) ^ 1x2

X = 13,842.18

Therefore, after a year has passed, Peyton's account will be $ 13,842.18.

7 0
3 years ago
A rectangle has a 15 to 20. Identify the ratio.
marishachu [46]

Answer:

15:20

15/20

15 to 20

there are 3 types of ways and there you go.

Step-by-step explanation:

have a great day ! :)

5 0
3 years ago
Read 2 more answers
The sum of Ted's and Leon's ages is
olganol [36]

Answer:

Ted is 6 years old

Leon is 7 years old

Andrew is 8 years old

Step-by-step explanation:

Ted+Leon=13 ⇒T+L=13 ⇒L=13-T

Leon+Andrew=15 ⇒L+A=15 ⇒A=15-L ⇒A=15-(13-T) because Leon =13-Ted

A=2+T

Ted+Andrew=14

T+A=14  ( substitute Andrew age from A=2+T)

T+2+T=14

2T=12

<h2>T=12/2=6 (Ted is 6 years old)</h2><h2>A=2+T=2+6=8 ( Andrew is 8 years old)</h2><h2>Leon=13-T=13-6=7 ( Leons is seven years old)</h2>

check: Ted+Leon=13 ⇒ 6+7=13

Leon + Andrew=15 ⇒7+8=15

Andrew+Ted=14 ⇒ 6+8=14

7 0
3 years ago
−76 = −0.8k <br><br> k =<br><br> What number represents k
Over [174]

Answer:

k= 95

Step-by-step explanation:

-76=-0.8k

-76/-0.8=k

95=k

k= 95

8 0
3 years ago
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