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Over [174]
3 years ago
9

A car travelling at 90km/h is 500m behind another car travelling at 70km/h in the same direction. How long will it take the firs

t car to catch the second?
Mathematics
1 answer:
MAXImum [283]3 years ago
6 0

Relative speed: 90 - 70 = 20 km/h

s = d ÷  t

t = d ÷  s

t = 500 m ÷ 20 km/h x 1000 m/h x 1 ÷ 60 hr/mins

t = 1.5 minutes.

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(3x + 3x²) + (2x² + 2x)?​
Galina-37 [17]

Answer:

=5x2+5x

Step-by-step explanation:

Let's simplify step-by-step.

3x+3x2+2x2+2x

8 0
3 years ago
Mike is looking for a loan. He is willing to pay no more than an effective rate of 8.000% annually. Which, if any, of the follow
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If Mike is willing to pay no more than an effective rate of 8.000% annually, the loans that meet his criteria are loan X and loan Z. Of those two, the lowest would be loan X.  I hope the answer will help you :)
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3 years ago
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What is the area of this face?
Paul [167]

Answer: I think it would be 30 ft

Step-by-step explanation: You would do LxW and get the anwer.

7 0
3 years ago
The distribution of resistance for resistors of a certain type is known to be normal, with 10% of all resistors having a resista
baherus [9]

Answer:

The mean is 9.65 ohms and the standard deviation is 0.2742 ohms.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

10% of all resistors having a resistance exceeding 10.634 ohms

This means that when X = 10.634, Z has a pvalue of 1-0.1 = 0.9. So when X = 10.634, Z = 1.28.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{10.634 - \mu}{\sigma}

10.634 - \mu = 1.28\sigma

\mu = 10.634 - 1.28\sigma

5% having a resistance smaller than 9.7565 ohms.

This means that when X = 9.7565, Z has a pvalue of 0.05. So when X = 9.7565, Z = -1.96.

Z = \frac{X - \mu}{\sigma}

-1.96 = \frac{9.7565 - \mu}{\sigma}

9.7565 - \mu = -1.96\sigma

\mu = 9.7565 + 1.96\sigma

We also have that:

\mu = 10.634 - 1.28\sigma

So

10.634 - 1.28\sigma = 9.7565 + 1.96\sigma

1.96\sigma + 1.28\sigma = 10.645 - 9.7565

3.24\sigma = 0.8885

\sigma = \frac{0.8885}{3.24}

\sigma = 0.2742

The mean is

\mu = 10.634 - 1.28\sigma = 10 - 1.28*0.2742 = 9.65

The mean is 9.65 ohms and the standard deviation is 0.2742 ohms.

8 0
3 years ago
If angle X is an acute angle with tan X = 8/7, what is the value of sec X?
iren [92.7K]

Answer: \frac{\sqrt{113}}{7}

Step-by-step explanation:

As X is an acute angle, all 6 trigonometric functions with an argument of X are positive.

Using the identity 1+\tan^{2} X=\sec^{2} X,

1+\left(\frac{8}{7} \right)^{2}=\sec^{2} X\\\\\sec^{2} X=\frac{113}{49}\\\\\therefore \sec X=\boxed{\frac{\sqrt{113}}{7}}

5 0
1 year ago
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