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expeople1 [14]
3 years ago
5

List the first 5 multiples, and find ALL the factors of 13

Mathematics
2 answers:
kvasek [131]3 years ago
7 0

Answer:


13,26,39,52,65,78 are the multiples 13 and 1 are the all of the factors


vladimir1956 [14]3 years ago
5 0

Hi There!

List the multiples and factors of 13:

Multiples: 13, 26, 39, 52, 65...

Factors: 1, 13...

Hope This Helps :)

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Consider the equation: 3(–4n – 9) = 21
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Answer: N=-4

Step-by-step explanation:

STEP

1

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STEP

2

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Pulling out like terms

2.1     Pull out like factors :

  -4n - 9  =   -1 • (4n + 9)

Equation at the end of step

2

:

 -3 • (4n + 9) -  21  = 0

STEP

3

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STEP

4

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Pulling out like terms

4.1     Pull out like factors :

  -12n - 48  =   -12 • (n + 4)

Equation at the end of step

4

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 -12 • (n + 4)  = 0

STEP

5

:

Equations which are never true:

5.1      Solve :    -12   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation:

5.2      Solve  :    n+4 = 0

Subtract  4  from both sides of the equation :

                     n = -4

One solution was found :

n = -4

7 0
2 years ago
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The manager of a snack bar buys bottled water in packs of 35 and candy bars in packs of 20. Then, she sells the items individual
cestrela7 [59]
4 packs of bottled water (35*4=140)
7 packs of candy bars (20*7=140)
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a file that is 226 megabytes is being downloaded. if the download is 15.1% complete how many megabytes have been downloaded
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The answer is 34.126(round it)
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If ABCD is congruent to EFGH, then stack BC with bar on top is congruent to ......?
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Step-by-step explanation:

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3 years ago
It has been said that newspapers are disappearing, replaced by various electronic media. In 2004, newspaper circulation (the num
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Answer:

A. y=-1.2x+59

B. 42.2 million

Step-by-step explanation:

Part A:

Given:

Newspapers circulated in year 2004, y_{1}=59\textrm{ million}

Newspapers circulated in year 2014, y_{2}=47\textrm{ million}

Let the time x start at the year 2004. So, x_{1}=0

For the year 2014, x_{2}=2014-2004=10

Therefore, linear relationship between newspapers circulated and time passed since 2004 is given as:

y-y_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}(x-x_{1})\\y-59=\frac{47-59}{10-0}(x-0)\\y-59=-\frac{12}{10}x\\y=-1.2x+59

Therefore, the equation describing the relationship is: y=-1.2x+59

Part B:

For the year 2018, x=2018-2004=14

Plug in 14 for x in the above equation and solve for y. This gives,

y=-1.2(14)+59\\y=-16.8+59\\y=42.2

Therefore, in the year 2018, the newspaper circulation will be 42.2 million.

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