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expeople1 [14]
3 years ago
5

List the first 5 multiples, and find ALL the factors of 13

Mathematics
2 answers:
kvasek [131]3 years ago
7 0

Answer:


13,26,39,52,65,78 are the multiples 13 and 1 are the all of the factors


vladimir1956 [14]3 years ago
5 0

Hi There!

List the multiples and factors of 13:

Multiples: 13, 26, 39, 52, 65...

Factors: 1, 13...

Hope This Helps :)

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2x2 + 2x - 1 when x = -3
myrzilka [38]
2x2+2x-1=
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4 0
2 years ago
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An engineer on the ground is looking at the top of a building. The angle of elevation to the top of the building is 22°. The eng
Pavlova-9 [17]
Let the distance from the engineer to the base of the building be x, then
tan 22 = 450/x
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3 years ago
Two bottled waters and an order of cheese nachos costs $5.50. Three bottled waters and two orders of cheese nachos costs $9.50.
cupoosta [38]

Answer:

1.50 for a water

2.80 for one nacho

Step-by-step explanation:

3w + 2n = 9.5

2w + 1n = 5.5

<em>good luck, i hope this helps :) </em>

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5 0
2 years ago
If h(x)=x-7 and g(x)=x^2, witch expresión is equivalent to(g*h)(5)?
Firdavs [7]

Answer: 4

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(g*h)(5) = 4

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8 0
2 years ago
Find the equation of the line that passes through point (6, 1) with the x-intercept of 2.
34kurt

<u>Answer:</u>

○ y = \frac{1}{4}x - \frac{1}{2}

<u>Step-by-step explanation:</u>

To find the equation of the line, let's first consider the points whose coordinates we have been given:

• (6, 1)

• (2, 0).

The point (2, 0) is what is called the x-intercept, which is the point where the line crosses the x-axis. This means that at this point, the y-coordinate of the line is 0.

Next, let's calculate the slope (gradient) of the line using the formula:

m = \frac{y_2 - y_1}{x_2 - x_1}

where:

m = gradient,

(x_2, y_2) and (x_1, x_2) = points on the line.

Using the formula:

m = \frac{1 - 0}{6 - 2}

⇒ m =\bf \frac{1}{4}

Finally, now that we have two points on the line as well as the line's slope, we can use the following formula to find the equation of the line:

\boxed{y - y_1 = m(x - x_1)}

You can use any of the points on the line as y_1 and x_1.

Using (2, 0):

y - 0 = \frac{1}{4}( x - 2)

⇒ y = \frac{1}{4}x - \frac{1}{2}

Therefore the equation of the line is y = \frac{1}{4}x - \frac{1}{2}.

Learn more about point-slope form at:

brainly.com/question/15143525

6 0
1 year ago
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