All categories

3 years ago

M<1= (2x + 7y) degrees and m<2= (2x+y) degrees find x and y

1 answer:

3 0

Do you have a picture for this problem? There are multiple different ways to solve this problem but I'll need a picture to help you.

You might be interested in

Free

Leona [35]

Answer:

thanks appreciated it

3 0

3 years ago

Read 2 more answers

Can we all agree that math is hard??

TEA [102]

Answer: sometimes

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Somebody please help! And show your work!

VARVARA [1.3K]

a= 34 degrees

b= 28 degrees

c= 62 degrees

Step-by-step explanation:

First you know that b is 1/2 of 56 degrees or 28.

The triangle with the a in it is isoceles because the two sides are both radii.

In the triangle the top angle = 112 because it is a centeral angle to the 112 arc.

Angle a and opposite to a are equal and then have to be 34 degrees to equal 180.

We know two arc lengths are 112 and 56 and the one with angle a has to be 34x2 or 68.

a whole circle equals 360.

360-56-68-112 = 124

Angle c = 1/2 of 124, or 62 degrees

6 0

3 years ago

Ten years ago 53% of American families owned stocks or stock funds. Sample data collected by the Investment Company Institute in

Alborosie

Answer:

a) Null hypothesis: $p\geq 0.53$

Alternative hypothesis: $p < 0.53$

b) $z=\frac{0.46 -0.53}{\sqrt{\frac{0.53(1-0.53)}{300}}}=-2.429$

$p_v =P(Z$

c) So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of American families owning stocks or stock funds is significantly less than 0.53 .

Step-by-step explanation:

Data given and notation

n=300 represent the random sample taken

$\hat p=0.46$ estimated proportion of American families owning stocks or stock funds

$p_o=0.53$ is the value that we want to test

$\alpha=0.01$ represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

Part a

We need to conduct a hypothesis in order to test the claim that proportion is less than 0.53 or 53%.:

Null hypothesis: $p\geq 0.53$

Alternative hypothesis: $p < 0.53$

Part b

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.46 -0.53}{\sqrt{\frac{0.53(1-0.53)}{300}}}=-2.429$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(Z$

Part c

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of American families owning stocks or stock funds is significantly less than 0.53 .

7 0

3 years ago

27^x −1 = 9^3x−7 what is X

tigry1 [53]

x is $\frac{11}{3}$