All categories

3 years ago

A nichrome wire has a resistance of 5

Physics

1 answer:

kari74 [83]3 years ago

4 0

Answer:

R = 6.67 Ohm's

Explanation:

Resistance is a property of a material that measures the opposition to the flow of current through the material. It is measured in Ohm's.

R = (ρl) ÷ A

where; R is the resistance of the material, A is its cross sectional area, l is its length and ρ is its resistivity.

For the first nichrome wire, resistance is 5 Ohm's.

i.e R = (ρl) ÷ A = 5 Ohm's

For the second nichrome wire, length = 4l, and area of cross section = 3A. The resistance of the second wire can be determined by;

R = (4ρl) ÷ 3A

= $\frac{4}{3}$ {(ρl) ÷ A}

= $\frac{4}{3}$ × 5

R = 6.67 Ohm's

Resistance of the second nichrome wire is 6.67 Ohm's.

You might be interested in

n isolated charged soap bubble of radius R0=7.45 cmR0=7.45 cm is at a potential of V0=307.0 volts.V0=307.0 volts. If the bubble

Gnesinka [82]

Complete Question

An isolated charged soap bubble of radius R0 = 7.45 cm is at a potential of V0=307.0 volts. V0=307.0 volts. If the bubble shrinks to a radius that is 19.0%19.0% of the initial radius, by how much does its electrostatic potential energy ????U change? Assume that the charge on the bubble is spread evenly over the surface, and that the total charge on the bubble r

Answer:

The difference is $U_f -U_i = 16 *10^{-7} J$

Explanation:

From the question we are told that

The radius of the soap bubble is $R_o = 7.45 \ cm = \frac{7.45}{100} = 0.0745 \ m$

The potential of the soap bubble is $V_1 =307.0 V$

The new radius of the soap bubble is $R_1 = 0.19 * 7.45=1.4155\ cm = 0.014155 \ m$

The initial electric potential is mathematically represented as

$U_i = \frac{V_1^2 R_o }{2k }$

The final electric potential is mathematically represented as

$U_f = \frac{V_2^2 R_1 }{2k }$

The initial potential is mathematically represented as

$V_1 = \frac{kQ}{R_o}$

The final potential is mathematically represented as

$V_2 = \frac{kQ}{R_1}$

Now

$\frac{V_2}{V_1} = \frac{R_o}{R_1}$

substituting values

$\frac{V_2}{V_1} = \frac{7.45}{1.4155} = \frac{1}{0.19}$

=> $V_2 = \frac{V_1}{0.19}$

$U_f = \frac{V_1^2 R_2 }{2k * 0.19^2}$

Therefore

$U_f -U_i = \frac{V_1^2 R_2 }{2k * 0.19^2} - \frac{V_1^2 R_o }{2k }$

$U_f -U_i = \frac{V_1^2}{2k} [\frac{ R_1 }{ * 0.19^2} - R_o]$

where k is the coulomb's constant with value $9*10^{9} \ kg\cdot m^3\cdot s^{-4}\cdot A^2.$

substituting values

$U_f -U_i = \frac{307^2}{9 * 10^{9}} [\frac{ 0.014155 }{ 0.19^2} - 0.0745]$

$U_f -U_i = 16 *10^{-7} J$

8 0

3 years ago

Wind and weather patterns are caused when warm air near the surface of the Earth rises to higher levels in the atmosphere. The a

fomenos

Convection is the answer

3 0

3 years ago

Read 2 more answers

Question 1(Multiple Choice Worth 2 points)

tia_tia [17]

Answer:

Explanation:

the reason for each column is to show the electronic configuration of the elements in that column.

Hope This Helps ▼・ᴥ・▼

3 0

3 years ago

Help fast plsss ! which statement is true for nuclear reactions but not for chemical reactions?

padilas [110]

Answer:

Explanation: a chemical reaction is only the rearrangement of electrons where a nuclear reaction actually changes the elements and thus the nuclei

5 0

3 years ago

The thickness of a book is 3.2cm, measured between the inside covers the highest level of page is 1096 what order of magnitude e

Naddik [55]

Answer:

Magnitude of Thickness has order of 2.919 × $10^{-5}$ m

Explanation:

Thickness of book is 3.2 cm.

Number of pages in the book is 1096.

Thickness of 1096 pages is 3.2 cm.

Thus, thickness of 1 page is $\frac{3.2}{1096}$ cm

Thickness of 1 page of book is 0.002919 cm

Magnitude of Thickness has order of 2.919 × $10^{-5}$ m

4 0

3 years ago