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ehidna [41]
3 years ago
11

Help fast plsss ! which statement is true for nuclear reactions but not for chemical reactions?

Physics
1 answer:
padilas [110]3 years ago
5 0

Answer:

B

Explanation: a chemical reaction is only the rearrangement of electrons where a nuclear reaction actually changes the elements and thus the nuclei

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How fast will a cart be moving if a force of 200 N is applied to a 50 kg cart for 10 sec?
jeka94

Acceleration = (force) / (mass)

If there is no friction . . .

Acceleration = (200N) / (50 kg) = 4m/s²

Change in speed = (acceleration) x (time) = (4 m/s²) x (10 sec) = 40 m/s

<em>Final speed = (speed of the cart before the force began) + (40 m/s more)</em>

(That's about <em><u>89 mph faster</u></em> than the cart was moving before the force started.)


8 0
3 years ago
Read 2 more answers
I though a=9.8 is in free fall?
Elina [12.6K]
9.8m/s^2, i’m not sure what you are asking
7 0
3 years ago
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Jupiter is 5.2 AU from the sun on average. How long is one year on Jupiter?
velikii [3]

Answer:

12 years

Explanation:

12 years is correct because how long is Jupiter one year is 12 years

3 0
2 years ago
A 0.14-MIN baseball is dropped from rest. It has a momentum of 0.90 kg⋅m/skg⋅m/s just before it lands on the ground.
nikitadnepr [17]

The time spent in the air by the ball at the given momentum is 6.43 s.

The given parameters;

  • <em>momentum of the ball, P = 0.9 kgm/s</em>
  • <em>weight of the ball, W = 0.14 N</em>

The impulse experienced by the ball is calculated as follows;

Ft = \Delta P

where;

Ft is impulse

\Delta P is change in momentum

The time of motion of the ball is calculated as follows;

t = \frac{\Delta P}{F} \\\\t = \frac{0.9 - 0}{0.14} \\\\t = 6.43 \ s

Thus, the time spent in the air by the ball at the given momentum is 6.43 s.

Learn more here:brainly.com/question/13468390

7 0
2 years ago
A 0.15 kg. baseball flies rightward at 15m/s to hit a tennis ball flying at it from
Serhud [2]
Let’s use *queue dramatic voice* THE GREAT LAW OF THE CONSERVATION OF MOMENTUM!!!!!

m1v1i + m2v2i = m1v1f + m2v2f

m1v1i - m1v1f = m2(v2f - v2i)

m2 = (m1v1i - m1v1f) / (v2f - v2i)

m2 = [(0.15)(15) - (0.15)(1.2)] / (13 - -22)

Henceforth, my good sire, the mass indeed works out to a fine approximate value of:
m = 0.06 kg

That’s a pretty small tennis ball!
4 0
3 years ago
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