Explanation:
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A block is pulled along a horizontal surface at a constant speed by a force (14.1i 0 j 5.1k). The direction k is perpendicular t
1 answer:
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Answer:
The velocity of the first block is 1.15m/s while of the second block 2.56m/s.
Explanation:
Momentum is only conserved in an isolated system, and because this problem requires us to find the value of the two variables, we need two equations; therefore, to conserved momentum the energy must be released in to the system only after the collision has occurred.
Therefore, from conservation of momentum
and from conservation of energy
Thus, we have two equations and two unknowns
which has solutions
and
Since the blocks cannot pass through each other, the 0.5kg block cannot have (moves to the left) while the 0.4 kg block has
(moves to the right); therefore, we take the first solution for the velocities:
.
Thus , the velocity of the first block is 1.15m/s while of the second block 2.56m/s.
Answer:
When the ball is held motionless above the floor, the ball possesses only GPE energy.If the ball is dropped, its GPE energy decreases as it falls.If the ball is dropped, its KE energy increases as it falls.
Explanation:
If the ball is held motionless, then its kinetic energy is equal to zero, since kinetic energy depends on the velocity. And the ball is held above the ground, which means it possesses gravitational potential energy.
If the ball is dropped, its height will decrease, therefore its gravitational potential energy will decrease. Along the way, the ball will be in free fall, and therefore its velocity will increase, hence its kinetic energy.