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3 years ago

Use the graph to determine the domain and range of the relation, and whether the relation is a function

Mathematics

1 answer:

ohaa [14]3 years ago

6 0

The answer is C. The domain is all points between -8 and 8 since it keeps waving back and forth. The range is all real numbers the graph continues on forever. And it is not a function because it does not pass the vertical line test

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A total of 70 tickets were sold for a concert and earn the organizers $804. If the cost of each ticket is either $10 or $12, how

crimeas [40]

Answer:

52 tickets cost $10 and 18 tickets cost $12

Step-by-step explanation:

10x+12y=804. (1)

x+y=70. (2)

From (2)

x=70-y

Substitute x=70-y into (1)

10x+12y=804

10(70-y)+12y=804

700-10y+12y=804

700+2y=804

2y=804-700

2y=104

y=104/2

y=52

Recall

x+y=70

x+52=70

x=70-52

x=18

52 tickets cost $10 and 18 tickets cost $12

5 0

3 years ago

Compare 5/6 and 1/3 using the benchmark fraction 1/2

fenix001 [56]

Answer:

Step-by-step explanation:

Denominators: 6 is 2 times more than 3

Make them common fractions

5/6 and 2/6

They are 3/6 apart, or 1/2 apart

8 0

3 years ago

What is 4/20 as a percent? And how do I find it?

Reika [66]

Well u know 4/20 equals 0.2 as a decimal but as a percentage it is 20% so 4/20 as a percentage is 20%

4 0

3 years ago

Try to sketch by hand the curve of intersection of the parabolic cylinder y = x2 and the top half of the ellipsoid x2 + 7y2 + 7z

vovikov84 [41]

Plug $y=x^2$ into the equation of the ellipsoid:

$x^2+7(x^2)^2+7z^2=49$

Complete the square:

$7x^4+x^2=7\left(x^4+\dfrac{x^2}7+\dfrac1{14^2}-\dfrac1{14^2}\right)=7\left(x^2+\dfrac1{14}\right)^2+\dfrac1{28}$

Then the intersection is such that

$7\left(x^2+\dfrac1{14}\right)^2+7z^2=\dfrac{1371}{28}$

$\left(x^2+\dfrac1{14}\right)^2+z^2=\dfrac{1371}{196}$

which resembles the equation of a circle, and suggests a parameterization is polar-like coordinates. Let

$x(t)^2+\dfrac1{14}=\sqrt{\dfrac{1371}{196}}\cos t\implies x(t)=\pm\sqrt{\sqrt{\dfrac{1371}{196}}\cos t-\dfrac1{14}}$

$y(t)=x(t)^2=\sqrt{\dfrac{1371}{196}}\cos t-\dfrac1{14}$

$z=\sqrt{\dfrac{1371}{196}}\sin t$

(Attached is a plot of the two surfaces and the intersection; red for the positive root $x(t)$ , blue for the negative)

4 0

3 years ago

I WILL GIVE BRAINLY! The surface of a table to be built will be in the shape shown below. The distance from the center of the sh

ki77a [65]

Answer:

draw lines center to vertex
43.5 square inches
261 square inches

Step-by-step explanation:

Part A:

The area can be decomposed into triangles by drawing a line from the center to each vertex of the hexagon.

Part B:

The area of each triangle is given by the triangle area formula:

A = (1/2)bh

A = (1/2)(10 in)(8.7 in) = 43.5 in²

Part C:

The area of the table top is 6 times the area of one triangle:

surface area = 6(43.5 in²) = 261 in²

3 0

3 years ago

Read 2 more answers