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3 years ago

Use the graph to determine the domain and range of the relation, and whether the relation is a function

Mathematics

1 answer:

ohaa [14]3 years ago

6 0

The answer is C. The domain is all points between -8 and 8 since it keeps waving back and forth. The range is all real numbers the graph continues on forever. And it is not a function because it does not pass the vertical line test

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A 'snail's pace is 60 inches per minute. At this rate how long will it take the snail to crawl 120 feet?

True [87]

Ok, so here, we have the unit rate of the snail. Now, we need to set up a proportion.

60/1 = 120/x

Now, cross multiply.

60*x = 120*1

60x= 120

Now divide to solve for x.

60x/60 = 120/60
x = 120/60
x= 2

Now our final answer is 2.

Final answer:- The snail will take 2 minutes to crawl 120 feet

5 0

3 years ago

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A captain and a co-captain are randomly selected from the 12 members of a fencing team. Determine the probability that Lauren is

Lilit [14]

I'm not 100% sure of this I think its as follows:-

Prob(Lauren then Isabel picked) = 1/12 * 1/11 = 1/132

4 0

3 years ago

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I BET NO ONE KNOWS THIS y varies jointly as x and z. y=20 when x=2 and z=5 . Find y when x=3 and z=6

Greeley [361]

Hello!

If y varies jointly with x and z, it'll mean that x and z are being multiplied by a factor "k", to equal y.

To give you a visual, this is what I mean.

$y=kxz$

That means we'll want to find $k$ with the first point we're given: $(2,20,5)$

$20=k(2)(5)$

$20=10k$

$k=2$

Which means our equation is:

$y=2xz$

Now, let's plug in the $x$ and $z$ from the other point to find $y$ .

$y=2(3)(6)$

$y=36$

Hope this helps!

6 0

3 years ago

PLEASE HELP AND ANSWER!!!!! Which of the following reveals the minimum value for the equation 2x2 + 12x − 14 = 0?

NARA [144]

Answer:

The correct option is 3.

Step-by-step explanation:

The given equation is

$2x^2+12x-14=0$

It can be written as

$(2x^2+12x)-14=0$

Taking out the common factor form the parenthesis.

$2(x^2+6x)-14=0$

If an expression is defined as $x^2+bx$ then we add $(\frac{b}{2})^2$ to make it perfect square.

In the above equation b=6.

Add and subtract 3^2 in the parenthesis.

$2(x^2+6x+3^2-3^2)-14=0$

$2(x^2+6x+3^2)-2(3^2)-14=0$

$2(x+3)^2-18-14=0$

$2(x+3)^2-32=0$ .... (1)

Add 32 on both sides.

$2(x+3)^2=32$

The vertex from of a parabola is

$p(x)=a(x-h)^2+k$ .... (2)

If a>0, then k is minimum value at x=h.

From (1) and (2) in is clear that a=2, h=-3 and k=-32. It means the minimum value is -32 at x=-3.

The equation $2(x+3)^2=32$ reveals the minimum value for the given equation.

Therefore the correct option is 3.

5 0

3 years ago

Point A is at (-2,4) and point C is at (4,7). Find the coordinates of point B on AC such that the ratio of a B to a C is 1:3

Diano4ka-milaya [45]

Answer:

$[x=\frac{1(4)+3(-2)}{1+3}, y=\frac{1(7)+3(4)}{1+3}]$

$[x=\frac{4-6}{4}, y=\frac{7+12}{4}]$

$[x=\frac{-2}{4}, y=\frac{19}{4}]$

$[x=-0.5, y=4.75]$

Therefore, the coordinates of point 'b' would be (-0.5 , 4.75).

Step-by-step explanation:

We have been given that point a is at (-2,4) and point c is at (4,7) .

We are asked to find the coordinates of point b on segment ac such that the ratio is 1:3.

We will use section formula to solve our given problem.

When point P divides a segment internally in the ratio m:n, the coordinates of point P would be:

$[x=\frac{mx_2+nx_1}{m+n}, y=\frac{my_2+ny_1}{m+n}]$

$\texttt{Let point} (-2,4)=(x_1,y_1) \texttt {and point} (4,7)=(x_2,y_2).$

$[x=\frac{1(4)+3(-2)}{1+3}, y=\frac{1(7)+3(4)}{1+3}]$

$[x=\frac{4-6}{4}, y=\frac{7+12}{4}]$

$[x=\frac{-2}{4}, y=\frac{19}{4}]$

$[x=-0.5, y=4.75]$

Therefore, the coordinates of point 'b' would be (-0.5 , 4.75).

5 0

3 years ago