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Helga [31]
3 years ago
5

(20 POINTS) ALGEBRA 1! PLEASE HELP ITS DUE IN A COUPLE MINS!

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
4 0

In height formulas, the last term of the formula is the starting height.

In this equation, the starting height would be 15 meters.

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Find the volume of the square pyramid, given its slant height​
Reptile [31]

Answer:

Step-by-step explanation:

base length b = 32 cm

slant height L = 30 cm

 

height h = √(L²-(½b)²)

= √(30²-0.25·32²)

≅ 25.3771550809 cm

 

volume V = (⅓)b²h

= (⅓)32²·25.38

≅ 8662.07 cm³

7 0
2 years ago
What graph represents the function f(x)= -x2+5?
ololo11 [35]
I hope it would helps

6 0
3 years ago
An elevator containing five people can stop at any of seven floors. What is the probability that no two people exit at the same
elena-s [515]

Answer:

Approximately 0.15 (360 / 2401.) (Assume that the choices of the 5 passengers are independent. Also assume that the probability that a passenger chooses a particular floor is the same for all 7 floors.)

Step-by-step explanation:

If there is no requirement that no two passengers exit at the same floor, each of these 5 passenger could choose from any one of the 7 floors. There would be a total of 7 \times 7 \times 7 \times 7 \times 7 = 7^{5} unique ways for these 5\! passengers to exit the elevator.

Assume that no two passengers are allowed to exit at the same floor.

The first passenger could choose from any of the 7 floors.

However, the second passenger would not be able to choose the same floor as the first passenger. Thus, the second passenger would have to choose from only (7 - 1) = 6 floors.

Likewise, the third passenger would have to choose from only (7 - 2) = 5 floors.

Thus, under the requirement that no two passenger could exit at the same floor, there would be only (7 \times 6 \times 5 \times 4 \times 3) unique ways for these two passengers to exit the elevator.

By the assumption that the choices of the passengers are independent and uniform across the 7 floors. Each of these 7^{5} combinations would be equally likely.

Thus, the probability that the chosen combination satisfies the requirements (no two passengers exit at the same floor) would be:

\begin{aligned}\frac{(7 \times 6 \times 5 \times 4 \times 3)}{7^{5}} \approx 0.15\end{aligned}.

5 0
2 years ago
Using​ 45-in. fabric, Regan needs 2 and one fourth yd for a​ dress, one fourth yd of contrasting fabric for the band at the​ bot
Arte-miy333 [17]

Answer:

7\dfrac14$ yards

Step-by-step explanation:

Regan needs the following:

2\dfrac{1}{4} yards for a​ dress

\dfrac{1}{4}$ yards of contrasting fabric for the band at the bottom$\\4\dfrac{3}{4}$ yards for a coordinating jacket.

Total Length of fabric needed

= 2\dfrac{1}{4}+\dfrac{1}{4}+4\dfrac{3}{4}\\=2+4+\dfrac{1}{4}+\dfrac{3}{4}+\dfrac{1}{4}\\=6+1+\dfrac{1}{4}\\=7\dfrac{1}{4}$ yards

The number of yards of 45-in. fabric needed is 7\dfrac14$ yards.

4 0
3 years ago
Read 2 more answers
Find the value of x (image below)
Hitman42 [59]

Answer:

x=35

Step-by-step explanation:

8 0
3 years ago
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