Find the value of x (image below)

Convert equation from slope intercept form to standard form y=-7/3x+1

Andrews [41]

Answer:

7x + 3y = 3

4 0

3 years ago

What is the correct way to check the solved equation<br> 4,127÷3=1,375 remainder 2<br>

Dafna11 [192]

the quickest way to do this would be to multiply 1,375 by 3 and then add 2.

1,375 * 3 = 4,125 + 2 = 4,127

correct!

6 0

3 years ago

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The diameter of the base of the cone measures 8 units. The height measures 6 units. A cone has a diameter of 8 units and a heigh

Brilliant_brown [7]

Answer: V = 100.48

Step-by-step explanation:

To get this value, you need to know the formula of the volume of the cone, which is:

V = π*r^2*h / 3

Where:

r: cone radius

h: height

π: value of pi which is 3.14

Now the radius, is half the diameter of base of the cone so:

r = 8 / 2 = 4 units

Now we have all the data needed to get the volume of the cone, let's use the expression given above:

V = 3.14 * (4)^2 * 6 / 3

V = 3.14 * 16 * 6 / 3

V = 301.44 / 3

V = 100.48

8 0

3 years ago

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2. Find the variation constant and an equation of variation where y varies inversely as x and y=9 when x=2.

Bas_tet [7]

Answer: y=108

Step-by-step explanation:

5 0

2 years ago

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The U.S. Energy Information Administration (US EIA) reported that the average price for a gallon of regular gasoline is $2.94. T

Anit [1.1K]

Answer:

a) 25

b) 67

c) 97

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample. In this problem, $\sigma = 0.25$

(a) The desired margin of error is $0.10.

This is n when M = 0.1. So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.1 = 1.96*\frac{0.25}{\sqrt{n}}$

$0.1\sqrt{n} = 1.96*0.25$

$\sqrt{n} = \frac{19.6*0.25}{0.1}$

$(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.1})^{2}$

$n = 24.01$

Rounding up to the nearest whole number, 25.

(b) The desired margin of error is $0.06.

This is n when M = 0.06. So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.06 = 1.96*\frac{0.25}{\sqrt{n}}$

$0.06\sqrt{n} = 1.96*0.25$

$\sqrt{n} = \frac{19.6*0.25}{0.06}$

$(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.06})^{2}$

$n = 66.7$

Rounding up, 67

(c) The desired margin of error is $0.05.

This is n when M = 0.05. So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.05 = 1.96*\frac{0.25}{\sqrt{n}}$

$0.05\sqrt{n} = 1.96*0.25$

$\sqrt{n} = \frac{19.6*0.25}{0.05}$

$(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.05})^{2}$

$n = 96.04$

Rounding up, 97

8 0

3 years ago