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e-lub [12.9K]
3 years ago
12

IN WHICH PLACE IS THE FIRST DIGIT IN THE QUOTIENT 1,497 by 5?

Mathematics
2 answers:
BabaBlast [244]3 years ago
6 0
The first digit of the quotient would be in the hundreds place.
Alecsey [184]3 years ago
3 0
1,497 ÷ 5 = 299.4.
Which place is the 2 in?
The 2 is in the hundreds place. To the left of the decimal, it goes ones, tens, hundreds, so on. To the right of the decimal, it goes tenths, hundredths, thousandths, so on.
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I can’t figure out how to solve this for a. I’ve tried multiple ways but still have not come up with an answer.
abruzzese [7]

Answer:

a = 33

Step-by-step explanation:

IN a parallelogram consecutive angles are supplementary, thus

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8 0
3 years ago
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What is the sum (Two-fifths x + StartFraction 5 over 8 EndFraction) + (one-fifth x minus one-fourth)?
liubo4ka [24]

The sum of  ( \frac{2}{5} x + \frac{5}{8} ) + ( \frac{1}{5} x - \frac{1}{4} ) is  \frac{3}{5} x +  \frac{3}{8}

Step-by-step explanation:

To add or subtract 2 fractions, they must have same denominators, if they not do that

  • Find the Lowest common multiple of the two denominators (LCM)
  • Replace each denominator by it
  • Divide The LCM by each denominator and multiply the numerator of each fraction by its quotient

∵ ( \frac{2}{5} x + \frac{5}{8} ) + ( \frac{1}{5} x - \frac{1}{4} )

- Let us start with adding the like terms

∴  ( \frac{2}{5} x + \frac{5}{8} ) + ( \frac{1}{5} x - \frac{1}{4} ) = (

∵ ( \frac{2}{5} x + \frac{1}{5} x ) have same denominators, then we can add them

∴ ( \frac{2}{5} x + \frac{1}{5} x ) = \frac{3}{5} x

∵  ( \frac{5}{8}  - \frac{1}{4} ) do not have the same denominators, then we must find

    LCM of 8 and 4

- The LCM of 8 and 4 is 8 because 8 is the first common multiple

   of 8 and 4

∵ LCM of 8 and 4 is 8

- Divide 8 by the denominator 4

∵ 8 ÷ 4 = 2

- Multiply the numerator of the fraction by 2

∴ \frac{1}{4}=\frac{2}{8}

∴  ( \frac{5}{8}  - \frac{1}{4} ) = ( \frac{5}{8} - \frac{2}{8} ) = \frac{3}{8}

∴  ( \frac{2}{5} x + \frac{5}{8} ) + ( \frac{1}{5} x - \frac{1}{4} ) = \frac{3}{5} x +  \frac{3}{8}

The sum of  ( \frac{2}{5} x + \frac{5}{8} ) + ( \frac{1}{5} x - \frac{1}{4} ) is  \frac{3}{5} x +  \frac{3}{8}

Learn more:

You can learn more about the fractions in brainly.com/question/2456302

#LearnwithBrainly

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svetoff [14.1K]
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5y - 7......u have 2 terms (5y and 7)...and it is the difference of 2 terms.

so ur answer is : 5y - 7


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