1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lunna [17]
3 years ago
9

Scientists estimate Earth's age to be 4.6 billion years. Samarium has a half-life of approximately 106 billion years. From the p

resent date, approximately how many more years must pass before a sample of samarium that was created at the beginning of Earth's history contains 25 percent of the original parent material? 10 billion 26 billion 100 billion 206 billion
Chemistry
2 answers:
Wewaii [24]3 years ago
8 0

1/4 Ao = Ao * ( 1/2)^(t/106)
t = 212
subtract 4.6 billion years
<span>d)</span>
Alexandra [31]3 years ago
4 0

Answer: Option (D)

Explanation: The following steps are shown how decay takes place-

  1. Samarium (Sm) initially had 100% of its parent material.
  2. Samarium undergoes radioactive decay and becomes half of it i.e 50% of its parent material.
  3. To Decay this 50% of its initial material, it takes 106 billion years.
  4. Again it undergoes radioactive decay and becomes half of it i.e 25%, and during this process it takes another 106 billion years.

So from the above question, the total number of years for Samarium to contain 25% of its parent material will be (106+106)=212 billion years.

it can also be calculated from the radioactive decay formula.

Thus the most approximate option provided here is option (D).

You might be interested in
Hydrogen peroxide decomposes to water and oxygen at constant pressure by the following reaction: 2H2O2(l) → 2H2O(l) + O2(g) ΔH =
Mashcka [7]

<u>Answer:</u> The amount of heat released is -7.203 kJ

<u>Explanation:</u>

The given chemical equation follows:

2H_2O_2(l)\rightarrow 2H_2O(l )+O_2(g);\Delta H=-196kJ

To calculate the enthalpy change for 1 mole of the hydrogen peroxide, we use unitary method:

When 2 moles of hydrogen peroxide is reacted, the enthalpy of the reaction is -196 kJ

So, when 1 mole of hydrogen peroxide will react, the enthalpy of the reaction will be \frac{-196}{2}\times 1=-98kJ

  • To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of hydrogen peroxide = 2.50 g

Molar mass of hydrogen peroxide = 34 g/mol

Putting values in above equation, we get:

\text{Moles of hydrogen peroxide}=\frac{2.50g}{34g/mol}=0.0735mol

  • To calculate the heat of the reaction, we use the equation:

\Delta H_{rxn}=\frac{q}{n}

where,

q = amount of heat released

n = number of moles = 0.0735 moles

\Delta H_{rxn} = enthalpy change of the reaction = -98 kJ/mol

Putting values in above equation, we get:

-98kJ/mol=\frac{q}{0.0735mol}\\\\q=(-98kJ/mol\times 0.0735mol)=-7.203kJ

Hence, the amount of heat released is -7.203 kJ

8 0
3 years ago
What is the systematic name of NaCl​
alekssr [168]

Answer:

The answer is Sodium chloride.

Na is sodium and Cl is chlorine.

6 0
2 years ago
A. Which reactant is the limiting reagent?
Tasya [4]

Answer:

a. Zinc is the limiting reactant.

b. m_{ZnBr_2}^{by\ Zn}=162.61gZnBr_2

c. m_{Br_2}^{leftover}=6.6g

Explanation:

Hello there!

a. In this case, when zinc metal reacts with bromine, the following chemical reaction takes place:

Zn+Br_2\rightarrow ZnBr_2

Thus, since zinc and bromine react in a 1:1 mole ratio, we can compute their reacting moles to identify the limiting reactant:

n_{Zn}=47.2g*\frac{1mol}{65.38g} =0.722molZn\\\\n_{Br_2}=122g*\frac{1mol}{159.8g} =0.763molBr_2

Thus, since zinc has the fewest moles we infer it is the limiting reactant.

b. Here, we compute the grams of zinc bromide via both reactants:

m_{ZnBr_2}^{by\ Zn}=0.722molZn*\frac{1molZnBr_3}{1molZn} *\frac{225.22gZnBr_2}{1molZnBr_2} =162.61gZnBr_2\\\\m_{ZnBr_2}^{by\ Br_2}=0.763molBr_2*\frac{1molZnBr_3}{1molBr_2} *\frac{225.22gZnBr_2}{1molZnBr_2} =171.95gZnBr_2

That is why zinc is the limiting reactant, as it yields the fewest moles of zinc bromide product.

c. Here, since just 0.722 mol of bromine would react, we compute the corresponding mass:

m_{Br_2}^{reacted}=0.722molBr_2*\frac{159.8gBr_2}{1molBr_2} =115.4gBr_2

Thus, the leftover of bromine is:

m_{Br_2}^{leftover}=122g-115.4g\\\\m_{Br_2}^{leftover}=6.6g

Best regards!

8 0
3 years ago
The total amount of matter of all of the organisms in an ecosystem is referred to as
saul85 [17]
I think the answer is bio mass
bio:life
mass:total
5 0
3 years ago
What is 188.5°F in Celsius?
zheka24 [161]

Answer:

That would be 86.944 Celsius

Explanation:

(188.5°F − 32) × 5/9 = 86.944°C

5 0
2 years ago
Read 2 more answers
Other questions:
  • Calculate the atomic mass of silicon. The three silicon isotopes have atomic masses and relative abundances of 27.9769 amu (92.2
    6·1 answer
  • The theoretical yield of 1,2-epoxycyclohexane is _______________ grams, when starting with 3.0 grams of trans-2-bromocyclohexano
    9·1 answer
  • A container with a fixed volume, filled with hydrogen gas at -104c and 71.8 kPa is heated until the pressure reaches 225.9 kPa.
    7·1 answer
  • Which of the following features is common to both acids and bases? A. ability to burn skin B. similar taste C. pH measurements g
    11·2 answers
  • At a certain temperature, the vapor pressure of pure benzene ‍ is atm. A solution was prepared by dissolving g of a nondissociat
    7·1 answer
  • The rate constant for this second‑order reaction is 0.610 M − 1 ⋅ s − 1 0.610 M−1⋅s−1 at 300 ∘ C. 300 ∘C. A ⟶ products A⟶product
    13·1 answer
  • How much heat in joules and in calories is required to heat at 28.4g( 1 oz) ice cube from -23C TO 1.0C
    13·1 answer
  • GIVING BRAINIEST FIVE STARS AND HEART! '
    7·2 answers
  • Mg (s) + 2 HCl (aq) --&gt; MgCl2 (aq) + H2 (g)
    13·1 answer
  • The electrolyte magnesium chloride (MgCl2) will break up into how many individual particles in water (what is the i value)?
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!