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3 years ago

The neck of a glass funnel is covered with wet filter paper why

Chemistry

2 answers:

Svetllana [295]3 years ago

7 0

Answer:

The neck of a glass funnel is covered with wet filter paper in sublimation process because it will slow down the rising of the warm gases and it will prevents them from escape.

Elenna [48]3 years ago

7 0

Answer:

The neck of a glass funnel is covered with wet filter paper in sublimation process because it will slow down the rising of the warm gases and it will prevents them from escape.

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For the following reaction, 4.31 grams of iron are mixed with excess oxygen gas . The reaction yields 5.17 grams of iron(II) oxi

natka813 [3]

Answer: The theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ....(1)

For Iron:

Given mass of iron = 4.31 g

Molar mass of iron = 53.85 g/mol

Putting values in above equation, we get:

$\text{Moles of iron}=\frac{4.31g}{53.85g/mol}=0.0771mol$

For the given chemical reaction:

$2Fe(s)+O_2(g)\rightarrow 2FeO(s)$

By Stoichiometry of the reaction:

2 moles of iron produces 2 moles of iron (ii) oxide.

So, 0.0771 moles of iron will produce = $\frac{2}{2}\times 0.0771=0.0771mol$ of iron (ii) oxide

Now, calculating the theoretical yield of iron (ii) oxide using equation 1, we get:

Moles of of iron (II) oxide = 0.0771 moles

Molar mass of iron (II) oxide = 71.844 g/mol

Putting values in equation 1, we get:

$0.0771mol=\frac{\text{Theoretical yield of iron(ii) oxide}}{71.844g/mol}=5.53g$

To calculate the percentage yield of iron (ii) oxide, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of iron (ii) oxide = 5.17 g

Theoretical yield of iron (ii) oxide = 5.53 g

Putting values in above equation, we get:

$\%\text{ yield of iron (ii) oxide}=\frac{5.17g}{5.53g}\times 100\\\\\% \text{yield of iron (ii) oxide}=93.49\%$

Hence, the theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %

7 0

3 years ago

Determain the number of moles in 2.24l of ch4 at stp

valkas [14]

Answer:

0.1 mole of CH₄

Explanation:

From the question given above, the following data were obtained:

Volume of CH₄ = 2.24 L

Number of mole of CH₄ =?

The number of mole of CH₄ can be obtained as follow:

Recall:

1 mole of a gas occupy 22.4 L at stp. This implies that 1 mole of CH₄ occupies 22.4 L at stp.

22.4 L = 1 mole of CH₄

Therefore,

2.24 L = 2.24 × 1 mole of CH₄ / 22.4

2.24 L = 0.1 mole of CH₄.

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3 years ago

Why does platinum metal make a good catalytic surface for reactant molecules?

d1i1m1o1n [39]

Answer:

it holds reactant molecules in a good position for then to react

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The convex lens of a magnifying glass is used to focus sunlight, as shown. Which of the lettered parts of the lens diagram repre

vesna_86 [32]

This is just a guess, but I do believe it is B

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3 years ago

How do I calculate the moles consumed in a vinegar titration?

Shtirlitz [24]

Answer: Use the titration formula

Explanation:

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4 years ago

The neck of a glass funnel is covered with wet filter paper why​

The neck of a glass funnel is covered with wet filter paper why