The answer is Cl because its oxidation number goes from a +7 down to a -1.
Answer: true
Explanation: i think its true
24.4 cm.
<h3>Explanation</h3>
HCl and NH₃ reacts to form NH₄Cl immediately after coming into contact. Where NH₄Cl is found is the place the two gases ran into each other. To figure out where the two gases came into contact, you'll need to know how fast they move relative to each other.
The speed of a HCl or NH₃ molecule depends on its <em>kinetic energy</em>.

Where
is the <em>kinetic energy</em> of the molecule,
its mass, and
the square of its speed.
Besides, the <em>kinetic theory</em> <em>of gases</em> suggests that for an ideal gas,

where
its temperature in degrees kelvins. The two quantities are directly proportional to each other. In other words, the <em>average kinetic energy</em> of molecules shall be the same for <em>any ideal gas </em>at the same<em> temperature</em>. So is the case for HCl and NH₃


Where
,
, and
the mass, speed, and kinetic energy of an HCl molecule;
,
, and
the mass, speed, and kinetic energy of a NH₃ molecule.
The ratio between the mass of an HCl molecule and a NH₃ molecule equals to the ratio between their <em>molar mass</em>. HCl has a molar mass of 35.45; NH₃ has a molar mass of 17.03. As a result,
. Therefore:



The <em>average </em>speed NH₃ molecules would be
<em>if</em> the <em>average </em>speed of HCl molecules
is 1.


As you know ethanol is a an alcohol and alcohol is a hydrocarbon. Alcohol is made up of a carbon chain which Is always non polar and a OH group which is polar. According to the solubility rule like substances dissolves like substance. Using ethanol chemical formula. Ethanol has a 2 carbon chain and a OH group. water is polar so it will be attracted to the OH group. Carbon chain on the other hand is nonpolar so it will be repelled from the water.
Therefore the Solubility of alcohols is determined by the stronger of the two forces. The strength of the attraction of the OH group, and the amount of water they dissolve in.
Answer:
How many molecules of water are there in 54 g of H2O H 2 O ? Solution. Molar Mass of H2O H 2 O = 2 + 16 = 18 g/moles. So ,number of moles of H2O H 2 O = Mass/Molar Mass = 54/18 =3 moles. Now 1 moles = 6.022×1023 6.022 × 10 23 molecule.