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3 years ago

How do you solve this equation? -5/4+(-7/9)= Thanks

Mathematics

1 answer:

Klio2033 [76]3 years ago

8 0

Answer:

-2 1/36 or -2.028

Step-by-step explanation:

tik(tok) slapddaddy

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if my grade is 69% what will my grade be if i got a 3.3 of 4 on a essay and it's worth 25% of my grade?

juin [17]

Answer:

72.4%

Step-by-step explanation:

The essay is 25% of your grade, and the rest is 75% of your grade.

25 (3.3/4) + 75 (0.69) ≈ 72.4

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3 years ago

Five-sixths of b is added to 7

Strike441 [17]

The answer would be 7+5/6b

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3 years ago

Read 2 more answers

Find the area of the polygon with vertices (1, 2) (1, -5) (5, -5) (5,2)

Svetradugi [14.3K]

Answer:

28 square units

Step-by-step explanation:

These vertices are written in the form of their x and y coordinates. Let

A=(1,2) ; B =(1,-5) ; C =(5, -5) ; D=(5,2)

The x points are 1, 1, 5, 5

The y points are 2,-5, -5, 2

The x extremes range from 1 to 5. The length in-between is 5-1 = 4

The y extremes range from -5 to 2. The length in-between is 2-(-5) = 7

Area of the polygon enclosed by the coordinates

= 4 x 7 = 28 square units

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2 years ago

Determine if the two triangles are congruent. If they are, state how you know.

Elza [17]

Angle-side-angle is a rule used to prove whether a given set of triangles are congruent. The ASA rule states that: If two angles and the included side of one triangle are equal to two angles and included side of another triangle, then the triangles are congruent

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2 years ago

If the original square had a side length of

irina [24]

Answer:

Part a) The new rectangle labeled in the attached figure N 2

Part b) The diagram of the new rectangle with their areas in the attached figure N 3, and the trinomial is $x^{2} +11x+28$

Part c) The area of the second rectangle is 54 in^2

Part d) see the explanation

Step-by-step explanation:

The complete question in the attached figure N 1

Part a) If the original square is shown below with side lengths marked with x, label the second diagram to represent the new rectangle constructed by increasing the sides as described above

we know that

The dimensions of the new rectangle will be

$Length=(x+4)\ in$

$width=(x+7)\ in$

The diagram of the new rectangle in the attached figure N 2

Part b) Label each portion of the second diagram with their areas in terms of x (when applicable) State the product of (x+4) and (x+7) as a trinomial

The diagram of the new rectangle with their areas in the attached figure N 3

we have that

To find out the area of each portion, multiply its length by its width

$A1=(x)(x)=x^{2}\ in^2$