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iren2701 [21]
3 years ago
14

Answer with work please

Mathematics
1 answer:
Delicious77 [7]3 years ago
4 0
Okayy what that is uh huh ?
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60 times 21 divided by 100 is 12.6
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Please help very urgent!!
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Answer:

  the n-th root of the ratio of ending to starting values, less 1

Step-by-step explanation:

When I have starting and ending values over a time period, I usually use those directly in the exponential equation. If you're asked for a percentage growth rate, then you have to convert the growth factor to a growth rate.

__

The exponential equation can be written ...

  f(t) = (initial value) × ((final value)/(initial value))^(t/(time period))

In your example case, this would be ...

  f(t) = 2 × (20/2)^(t/18)

  f(t) = 2(10^(t/18)) . . . . . . simplified

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To convert this to the form ...

  f(t) = 2(1 +(growth rate))^t

recognize that ...

  (1 +(growth rate)^t = (10^(1/18))^t

So, you need to find the value of ...

  10^(1/18) = 10^(1/18) ≈ 1.13646 = 1 + 13.646%

Then the growth rate is about 13.6% each week.

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Sometimes, you want to use this in the form ...

  f(t) = (initial value)×(1 + (growth rate))^t

and sometimes you want the form ...

  f(t) = (initial value)×e^(kt)

When you solve for k, you find it is ...

  k = ln(1 + (growth rate)) . . . . . . . . where ln(x) is the natural logarithm of x

Here, that is ...

  k = ln(10^(1/18)) = ln(10)/18 ≈ 0.12792

__

Your final growth equation could be any of ...

  f(t) = 2(10^(t/18)) . . . . . . . my personal favorite, as no rounding is involved

  f(t) = 2(1.13646^t)

  f(t) = 2e^(0.12792t)

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