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iren2701 [21]
3 years ago
14

Answer with work please

Mathematics
1 answer:
Delicious77 [7]3 years ago
4 0
Okayy what that is uh huh ?
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We have been given graph of a downward opening parabola with vertex at point (6.5,42.25). We are asked to write equation of the parabola in standard form.

We know that equation of parabola in standard form is f(x)=ax^2+bx+c.

We will write our equation in vertex form and then convert it into standard form.

Vertex for of parabola is y=a(x-h)^2+k, where point (h,k) represents vertex of parabola and a represents leading coefficient.

Since our parabola is downward opening so leading coefficient will be negative.

Upon substituting coordinates of vertex and point (0,0) in vertex form, we will get:

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f(x)=-(x^2-13x+42.25)+42.25

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