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IgorC [24]
3 years ago
13

The unknowns are a mixture of ferrous ammonium sulfate and ammonium sulfate. calculate the amount of ferrous ammonium sulfate an

d the amount of ammonium sulfate needed to prepare a sample that is 10% fe with a total mass of 0.2 g
Chemistry
1 answer:
kumpel [21]3 years ago
7 0

Answer: -

Molar mass of ferrous ammonium sulfate =392 g / mol

Mass of iron present in ferrous ammonium sulfate = 56 g/mol

Total mass required = 0.2 g

Total mass of iron Fe required = 10% of 0.2 g

                                           = \frac{10}{100}x0.2

                                            = 0.02 g

Only ferrous ammonium sulfate has iron. So all iron must be present only as ferrous ammonium sulfate.

56 g of iron is present in 392 g of ferrous ammonium sulfate

0.02 g of iron is present in \frac{392}{56} x 0.02

                                                       = 0.14 g

Mass of ammonium sulfate = 0.2 - 0.14 = 0.06 g

Thus the required composition must be 0.06 g ammonium sulfate and 0.14 g ferrous ammonium sulfate.

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The acid-dissociation constant of hydrocyanic acid (hcn) at 25.0 °c is 4.9 ⋅ 10−10. what is the ph of an aqueous solution of 0.0
vodomira [7]
According to the reaction equation:

and by using ICE table:

              CN-  + H2O ↔ HCN  + OH- 

initial  0.08                        0          0

change -X                        +X          +X

Equ    (0.08-X)                    X            X

so from the equilibrium equation, we can get Ka expression

when Ka = [HCN] [OH-]/[CN-]

when Ka = Kw/Kb

               = (1 x 10^-14) / (4.9 x 10^-10)

               = 2 x 10^-5

So, by substitution:

2 x 10^-5 = X^2 / (0.08 - X)

X= 0.0013

∴ [OH] = X = 0.0013 

∴ POH = -㏒[OH]

            = -㏒0.0013

            = 2.886 

∴ PH = 14 - POH

         = 14 - 2.886 = 11.11
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3 years ago
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Studentka2010 [4]
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3 years ago
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A compound of carbon and hydrogen contains 92.3 percent c and has a molar mass of 78.1g/mol. What is its molecular
alekssr [168]

Answer:

C₆H₆

Explanation:

We need to find the molecular formula of a compound of carbon (C) and hydrogen (H), so what <em>we need to find out is the number of atoms of C and of  H in the molecule.</em> We know:

  • molar mass = 78.1 g/mol
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So, in 1 mol of compound, 92.3% of the mass corresponds to Carbon:

<u>mass of C / mol of compound</u> = molar mass × C% = 78.1 g/mol × 92.3/100 = <u>72.1 g/mol</u>

<u>moles of C</u> = mass C / molar mass C = 72.1 g / 12.011 g/mol

moles of C = 6 moles of C per mol of compound

If 72.1 g in a mol of compound are Carbon atoms, the difference between the molar mass and the mass of Carbon atoms will correspond to H atoms in 1 mol of compound:

<u>mass of H / mol of compound</u> = molar mass - mass of C/mol

mass of H = 78.1 g / mol - 72.1 g /mol = <u>6.0 g/mol of compound</u>

<u>moles of H</u> = mass H / molar mass H = 6.0 g / 1.008 g/mol

moles of H = 6.0 moles of H per mol of compound

<em>So</em><em> one mol of compound has 6 moles of C and 6 moles of H.</em>

The molecular formula is then written as C₆H₆

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abruzzese [7]

Answer:

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pashok25 [27]

Answer:

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Explanation:

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I hope it helps.

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3 years ago
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