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prohojiy [21]
2 years ago
11

Help me please!!!!!!!!!!!!!!!!!!!!!!!! almost deadline!!!!!!!!!!!!!!!!!!!!!!!!!

Chemistry
1 answer:
astraxan [27]2 years ago
3 0

Answer:A

Explanation:I hope I’m right

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slavikrds [6]
These are not questions but the directions or guide to completing your assignment.

I will provide you will with a choice of concept maps you can use:

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Please vote my answer branliest! Thanks.
8 0
4 years ago
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What is the boiling point of<br> gold<br> 1064.43°C<br> 2970°C<br> 1313°C<br> 3266°C
Vikentia [17]

Answer:

The melting point of Gold is 1064.43 degrees celsius and the boiling point is 2807 degrees celsius.

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4 years ago
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Write the balanced equation for the combustion of isooctane to produce water vapor and carbon dioxide gas.Assuming gasoline is i
tangare [24]

Answer:

The yield is 16 moles of CO2 per 2 moles of isooctane.

The mass of CO2 is 1.15 billion tonnes

Explanation:

First we set the unbalanced equation:

C_{8}H_{18} + O_{2} \longrightarrow CO_{2} + H_{2}O

Now we proceed to balance the equation:

2C_{8}H_{18} + 25O_{2} \longrightarrow 16CO_{2} + 18H_{2}O

With the equation balanced, we see that the theoretical yield is 16 moles of CO2 per 2 moles of isooctane and we can proceed to make calculations with the following data:

\rho _{C_{8}H_{18}}=0.69 g/mL\\Consumption: 142.86x10^{9} gal\\1gal=3785.41 mL\\M_{C_{8}H_{18}}=114.23g/mole\\M_{CO_{2}}=44.01g/mole\\

Knowing the different relations between mass, density and molar mass, we have the following results:

V_{C_{8}H_{18}}=5.41x10^{14}mL\\m_{C_{8}H_{18}}=3.73x10^{14}g\\n_{C_{8}H_{18}}=3.27x10^{12}mole\\n_{CO_{2}}=2.62x10^{13}mole\\m_{CO_{2}}=1.15x1015g\\m_{CO_{2}}=1.15x10^{9}tonnes

8 0
4 years ago
A liter is the same as a _____.
Nata [24]
Hope this helped :) you
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3 years ago
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How many cm3 are there in 0.25 dm3?
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250cm3 i think im not sure about it though
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