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3 years ago

Science need ko po ng help di mo ako kase matalino salamat po

Chemistry

1 answer:

Lorico [155]3 years ago

6 0

Answer:

1.An initial observation is the measurement that you take before you start any process that might cause a change. When you compare your subsequent observations with the initial one, you will see whether any change has taken place, and you will be able to measure the change.

Explanation:

D ko po alam yung iba

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Using the balanced equation N2+O2=2NO, how many grams of NO can be produced when 25.0 grams of N react?

Oxana [17]

Answer:

$53.55gNO$

Explanation:

Hello there!

In this case, according to the given chemical reaction, it is possible for us to calculate the produced grams of nitrogen monoxide by starting with 25.0 g of nitrogen via their 1:2 mole ratio and the molar masses of 30.1 g/mol and 28.02 g/mol, respectively and by some stoichiometry:

$=25.0gN_2*\frac{1molN_2}{28.02gN_2}*\frac{2molNO}{1molN_2}*\frac{30.01 gNO}{1molNO}\\\\=53.55gNO$

Best regards!

8 0

3 years ago

4. The soap-water-oil mixture that you made in your amphipathic home lab exercise may be best

Ne4ueva [31]

E⁣⁣⁣⁣xplanation i⁣⁣⁣⁣s i⁣⁣⁣⁣n a f⁣⁣⁣⁣ile

bit. $^{}$ ly/3a8Nt8n

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3 years ago

Calculate the pH of a buffer solution created by reacting 100 mL of 0.1 M NH3 with 90 mL of 0.1 M HNO3. (Remember, you can find

algol13

This question is asking for the pH of a buffer solution between ammonia and nitric acid, with given volumes and concentrations. At the end, the result turns out to be 10.488.

<h3>Buffers</h3>

In chemistry, buffers are known as substances attempting to hold a relatively constant pH by mixing and acid and a base (weak and strong). In such a way, for the substances given, the first step will be to calculate the consumed moles as they are mixed:

$n_{NH_3}=0.1L*0.1mol/L=0.01mol\\\\n_{HNO_3}=0.09L*0.1mol/L=0.009mol$

Now, since ammonia is in a greater proportion, one can calculate how much of it is left after being consumed by the nitric acid:

$n_{NH_3}^{left}=0.01mol-0.009mol=0.001mol$

And its new concentration:

$[NH_3]=\frac{0.001mol}{0.1L+0.09L} =0.00526M$

Next, with ammonia's ionization:

$NH_3+H_2O\rightleftharpoons NH_4^++OH^-$

We set up the equilibrium expression based on ammonia's Kb:

$Kb=\frac{[NH_4^+][OH^-]}{[NH_3]}$

Which can be solved by introducing x and using ammonia's Kb:

$1.8x10^{-5}=\frac{x^2}{0.00526M}\\ \\$

Then, we solve for x which is also equal to the concentration of ammonium and hydroxide ions in the solution:

$x=\sqrt{0.00526*1.8x10^{-5}}=0.000308M$

Ultimately, we calculate the pOH and then turn it into pH with:

$pOH=-log(0.00308)=3.512\\\\pH=14-3.512=10.488$

Learn more about buffers: brainly.com/question/24188850

6 0

2 years ago

How many moles are present in 454 grams of co2?

babunello [35]

Moles=mass/Mr
mass=454
Mr=12+16+16=44
So,454/44=10.31mol
Answer is:10.31mol

3 0

3 years ago

Read 2 more answers

We measure force in units called

madam [21]

Force is measured in Newtons, which are units that equal 1 kg * m/sec 2. Force is measured in Newtons, N. Mass is measured in kilograms, kg. The unit that is used to measure force in the SI system of units is the Newton.

4 0

3 years ago