<span>the particle's initial position is at t=0, x = 0 - 0 + 4 = 4m
velocity is rate of change of displacement = dx/dt = d(t^3 - 9t^2 +4)/dt
= 3t^2 - 18t
acceleration is rate of change of velocity = d(3t^2 -18t)/dt
= 6t - 18
</span><span>the particle is stationary when velocity = 0, so 3t^2 - 18t =0
</span>3t*(t - 6) = 0
t = 0 or t = 6s
acceleration = 6t - 18 = 0
t = 3s
at t = 3s, velocity = 3(3^2) -18*3 = -27m/s
displacement = 3^3 - 9*3^2 +4 = -50m
Step-by-step explanation:
domain is the valid interval for the x (input) values for the function.
the range is the valid interval for the y (result) values of the function.
so, we have a function definition and a valid domain interval for x. we therefore try the x values and see what result values they create. and that defines the range.
x = -6
y = 4 - -6 = 4 + 6 = +10
c
x = 2
y = 4 - 2 = +2
x = 7
y = 4 - 7 = -3
we have therefore a range of {-3, 2, 10}
Answer: 216, 343, 512, 729, 1000, 1331, 1728, 2197, 2744
Step-by-step explanation: The terms are the cubes of the numbers 1, 2, 3, 4, 5...
Megan beacuse he says 10 numbers
And lee says 4 number
