The objective function is simply a function that is meant to be maximized. Because this function is multivariable, we know that with the applied constraints, the value that maximizes this function must be on the boundary of the domain described by these constraints. If you view the attached image, the grey section highlighted section is the area on the domain of the function which meets all defined constraints. (It is all of the inequalities plotted over one another). Your job would thus be to determine which value on the boundary maximizes the value of the objective function. In this case, since any contribution from y reduces the value of the objective function, you will want to make this value as low as possible, and make x as high as possible. Within the boundaries of the constraints, this thus maximizes the function at x = 5, y = 0.
Y= -1/3x+5
the y-intercept is 5 and the slope is -1/3
Answer:
x<100
Step-by-step explanation:
The given equation is :
x-19<81
Adding 19 to both sides of the equation.
x-19+19<81+19
x<100
It means the solution of the given equation is less than 100. Hence, the attached figure shows the graph for the given equation.
The initial value is 3. The common ratio is -9/3 = -3. The general formula is
.. an = a1*r^(n-1)
So, for your values, ...
.. an = 3*(-3)^(n -1)
Answer:
The answer to your question is speed = 81.5 mi/h
Step-by-step explanation:
Data
distance = 230 ft
time = 1.932 s
speed = ? mi/h
Process
1.- Convert the distance to mi
1 mile ----------------- 5280 ft
x ----------------- 230 ft
x = (230 x 1) / 5280
x = 0.044 mi
2.- Convert time to hours
1 h ------------------ 3600 s
x ------------------ 1.932 s
x = (1.932 x 1) / 3600
x = 0.00054 h
3.- Calculate the speed
speed = distance / time
-Substitution
speed = 0.044/ 0.00054
-Result
speed = 81.5 mi/h
