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a_sh-v [17]
3 years ago
12

I Need Help with my homework. It’s due tomorrow and i don’t know anything about algebra

Mathematics
2 answers:
Arlecino [84]3 years ago
7 0
The number in the parenthesis will be your x value so you can just plug them in the equation given to you and solve.

In number 1, g(x) = -5x + 2. 1a gives you g(-1). That -1 inside that g(-1) will be your x.
g(-1) = -5(-1) + 2
g(-1) = 5 + 2
g(-1) = 7

For 1b, you have g(-2) so you plug -2 everywhere the x is.
g(-2) = -5(-2) + 2
g(-2) = 12

For 3a, you have a different equation: x^2 + 4x - 1 and you have g(-4). Not a problem though just plug -4 into all the places x is at and solve.
g(-4) = -4^2 + 4(-4) - 1
= 16 - 16 - 1
= -1

Hope this helped
kow [346]3 years ago
5 0
Simply plug a in for x where f(a) means x=a
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Please help me solve this.<br>​
erastovalidia [21]

Answer:

B. Subtract 7

Step-by-step explanation:

You always want to isolate the <em>x</em> term to solve for <em>x</em> in any equation. Therefore, we need to move the 7 to the other side. Only way to do that is to subtract 7 on both sides.

8 0
3 years ago
Lindsay draws a right triangle and adds the measures of the right angle and one acute angle. Which is a possible sum of the two
Anon25 [30]
Anything between 91 degrees and 179 degrees. You can pick any between these two.
6 0
3 years ago
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The function g(x) = x2 is transformed to obtain function h:
Westkost [7]
I think B is correct
8 0
3 years ago
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Rewrite the quadratic function in vertex form (which is also called a standard form) and give the vertex.
jasenka [17]

The vertex form of the equation f(x) = x^2 - 3x, is f(x) = (x - 3/2)^2 - 9/5

<h3>How to rewrite the quadratic function?</h3>

The quadratic function is given as:

f(x) = x^2 - 3x

Differentiate the function

f'(x) = 2x - 3

Set the function to 0

2x - 3 = 0

Add 3 to both sides

2x = 3

Divide by 2

x = 3/2

Set x = 3/2 in f(x) = x^2 - 3x

f(x) = 3/2^2 - 3 * 3/2

Evaluate

f(x) = -9/5

So, we have:

(x, f(x)) = (3/2, -9/5)

The above represents the vertex of the quadratic function.

This is properly written as:

(h, k) = (3/2, -9/5)

The vertex form of a quadratic function is

f(x) = a(x - h)^2 + k

So, we have:

f(x) = a(x - 3/2)^2 - 9/5

In f(x) = x^2 - 3x,

a = 1

So, we have:

f(x) = (x - 3/2)^2 - 9/5

Hence, the vertex form of the equation f(x) = x^2 - 3x, is f(x) = (x - 3/2)^2 - 9/5

Read more about vertex form at

brainly.com/question/24850937

#SPJ1

7 0
1 year ago
Which graph represents the following system of equations?<br> y=x+4<br> y=-3/5x+1
viktelen [127]
Option one, cuz u can see that the equation y=x+4 can best suit the red line while the second can fit the blue. U can try some numbers to check
3 0
2 years ago
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