You have two 30-60-90 triangles, ADC and BDC.
The ratio of the lengths of the sides of a 30-60-90 triangle is
short leg : long leg : hypotenuse
1 : sqrt(3) : 2
Using triangle ADC, we can find length AC.
Using triangle BDC, we can find length BC.
Then AB = AC - BC
First, we find length AC.
Look at triangle ACD.
DC is the short leg opposite the 30-deg angle.
DC = 10sqrt(3)
AC = sqrt(3) * 10sqrt(3) = 3 * 10 = 30
Now, we find length BC.
Look at triangle BCD.
For triangle BCD, the long leg is DC and the short leg is BC.
BC = 10sqrt(3)/sqrt(3) = 10
AB = AC - BC = 30 - 10 = 20
Answer:
3: 200, 200
4:800
5:400
Step-by-step explanation:
:)
Answer:
1/2 (x+5) = 36 should be the equation that is used to determine how many rocks George started with.
Step-by-step explanation:
Let 'x' be the number of rocks George had.
As George gave, after getting 5 new rocks, half of his rock collection to Susan which is = 36 rocks
It means after getting 5 new rocks George's total rocks = 72
Given that he gave half collection to Susan = 36
Thus, before inducting 5 new rocks Georg's total rocks were = 67
Thus,
1/2 (x+5) = 36 should be the correct equation.
solving
1/2 (x+5) = 36
Multiplying both sides by 2
1/2 (x+5) × 2 = 36 × 2
x+5 = 72
x = 72 - 5
x = 67
Thus, before getting 5 new rocks, the number of rocks George had = 67
Therefore,
1/2 (x+5) = 36 should be the equation that is used to determine how many rocks George started with.
The Lagrangian,

has critical points where its partial derivatives vanish:





tells us
, so that


Then with
, we get

and
tells us

Then there are two critical points,
. The critical point with the negative
-coordinates gives the maximum value,
.