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Tasya [4]
3 years ago
8

Four cousins were born at two-year intervals. The sum of their ages is 36. How old are they?

Mathematics
2 answers:
UNO [17]3 years ago
7 0
They are 6, 8, 10, 12 years old.

all of those added is 36 and two-year intervals translates to 2 years apart per cousin.
Free_Kalibri [48]3 years ago
3 0

Answer:

6, 8, 10, 12

Step-by-step explanation:

x + (x + 2) + (x + 4) + (x + 6) = 4x + 12.

4x + 12 = 36

24 = 4x

x = 6

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~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ R(\stackrel{x_1}{-7}~,~\stackrel{y_1}{5})\qquad S(\stackrel{x_2}{17}~,~\stackrel{y_2}{5}) ~\hfill RS=\sqrt{(~~ 17- (-7)~~)^2 + (~~ 5- 5~~)^2} \\\\\\ ~\hfill RS=\sqrt{( 24)^2 + ( 0)^2}\implies \boxed{RS=24} \\\\\\ S(\stackrel{x_1}{17}~,~\stackrel{y_1}{5})\qquad T(\stackrel{x_2}{5}~,~\stackrel{y_2}{0}) ~\hfill ST=\sqrt{(~~ 5- 17~~)^2 + (~~ 0- 5~~)^2}

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