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galina1969 [7]
2 years ago
6

Multiply 3x (2x - 1)​

Mathematics
2 answers:
Volgvan2 years ago
6 0

Answer:

6x^2 - 3x

6x^2-3x

Step-by-step explanation:

3x (2x-1)

multiply 3x by 2x -> 6x^2

multiply 3x by -1 -> -3x

finlep [7]2 years ago
6 0

Answer:

The answer is 6x^{2} -3x.

Step-by-step explanation:

To solve for the answer, start by using the distributive property. The distributive property is a property of multiplication used in addition and subtraction and states that two or more terms in addition or subtraction with a number are equal to the addition or subtraction of the product of each of the terms with that number.

The distributive property for this problem will look like (3x*2x)+(3x*-1), and when the problem is simplified, it will look like 6x^{2} -3x. The final answer is 6x^{2} -3x.

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Find three consecutive even integers such that 3 times the first is 26 less than twice the sum of the last two
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Let's say our first integer is "a".

how to get the next consecutive EVEN integer?  well, just add or subtract 2 from it, therefore, the second consecutive integer will be "a + 2".

and the next after that, will then be (a + 2) + 2, or "a + 4".

so those are are 3 integers, a           a + 2           a+4

notice that, from any even or odd integer, if you hop twice either forwards or backwards, you'll land on another even or odd integer respectively.

2 + 2 is 4, or 8 + 2 is 10  some even ones

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\bf \stackrel{\textit{3 times the first}}{3a}~~=~~\stackrel{\textit{26 less than twice the sum of the others}}{2[~(a+2)+(a+4)~]~~~-26}
\\\\\\
3a=2[~2a+6~]-26\implies 3a=4a+12-26\implies 3a=4a-14
\\\\\\
0=a-14\implies 14=a

what are the other two consecutive integers?  well, a + 2 and a + 4.
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