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galina1969 [7]
2 years ago
6

Multiply 3x (2x - 1)​

Mathematics
2 answers:
Volgvan2 years ago
6 0

Answer:

6x^2 - 3x

6x^2-3x

Step-by-step explanation:

3x (2x-1)

multiply 3x by 2x -> 6x^2

multiply 3x by -1 -> -3x

finlep [7]2 years ago
6 0

Answer:

The answer is 6x^{2} -3x.

Step-by-step explanation:

To solve for the answer, start by using the distributive property. The distributive property is a property of multiplication used in addition and subtraction and states that two or more terms in addition or subtraction with a number are equal to the addition or subtraction of the product of each of the terms with that number.

The distributive property for this problem will look like (3x*2x)+(3x*-1), and when the problem is simplified, it will look like 6x^{2} -3x. The final answer is 6x^{2} -3x.

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Naomi just accepted a job at a new company where she will make an annual salary of $66000. Naomi was told that for each year she
Vaselesa [24]

Answer:

$82,000

$66,000 + $4000t

Step-by-step explanation:

Initial annual salary = $66,000

Salary raise per year = $4000

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$66,000 + ($4000 * 4)

$66,000 + $16,000

= $82,000

Salart after t years :

Initial salary + (raise per year * number of years)

$66,000 +.($4000 * t)

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3 0
2 years ago
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Verify that P = Ce^t /1 + Ce^t is a one-parameter family of solutions to the differential equation dP dt = P(1 − P).
NemiM [27]

Answer:

See verification below

Step-by-step explanation:

We can differentiate P(t) respect to t with usual rules (quotient, exponential, and sum) and rearrange the result. First, note that

1-P=1-\frac{ce^t}{1+ce^t}=\frac{1+ce^t-ce^t}{1+ce^t}=\frac{1}{1+ce^t}

Now, differentiate to obtain

\frac{dP}{dt}=(\frac{ce^t}{1+ce^t})'=\frac{(ce^t)'(1+ce^t)-(ce^t)(1+ce^t)'}{(1+ce^t)^2}

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To obtain the required form, extract a factor in both the numerator and denominator:

\frac{dP}{dt}=\frac{ce^t}{1+ce^t}\frac{1}{1+ce^t}=P(1-P)

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Answer:

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Step-by-step explanation:

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