Step-by-step explanation:
f(x) = x² + x + 3/4
in general, such a quadratic function is defined as
f(x) = a×x² + b×x + c
the solution for finding the values of x where a quadratic function value is 0 (there are as many solutions as the highest exponent of x, so 2 here in our case)
x = (-b ± sqrt(b² - 4ac))/(2a)
in our case
a = 1
b = 1
c = 3/4
x = (-1 ± sqrt(1² - 4×1×3/4))/(2×1) =
= (-1 ± sqrt(1 - 3))/2 = (-1 ± sqrt(-2))/2 =
= (-1 ± sqrt(2)i)/2
x1 = (-1 + sqrt(2)i) / 2
x2 = (-1 - sqrt(2)i) / 2
remember, i = sqrt(-1)
f(x) has no 0 results for x = real numbers.
for the solution we need to use imaginary numbers.
Answer: 11 year
P(1) = 37,100
P(4) = 58,400
The linear equation (for x ≥ 1)
P(x) = 37,100 + a(x-1)
For x = 4
58,400 = 37,100 + a(4-1)
58,400 - 37,100 = 3a
21300 = 3a
a = 7100
So, the linear equation:
P(x) = 37100 + 7100*(x-1)
P(x) = 37100 + 7100x - 7,100
P(x) = 7100x + 30000
To find when the profit should reach 108100, we can substitute P(x) by 108100.
108100 = 7100x + 30000
108100 - 30000 = 7100x
78100 = 7100x
x = 78100/7100
x = 11
Answer: 11 year
For this case we must find
By definition we have to:
We have the following functions:
Now, applying the given definition, we have:
Answer:
Answer:
3x3-45÷(4+1) is 0.
Step-by-step explanation:
We have to do order of operations so we follow PEMDAS:
P is for Parentheses so we do what's in parentheses first:
(4+1)=5
E is for Exponents but we don't have exponents.
Next is M and D for Multiplication and Division. We have division before multiplication so we should do division first:
45÷5=9
We now have multiplication:
3x3=9
Now we have A and S for addition and subtraction
We don't have addition so we'll do subtraction:
9-9=0
The final answer is 0.
Hope this helps! :)
<h3>
CloutAnswers</h3>
The correct answer is -1/3.
