Answer: Option (b) is the correct answer.
Explanation:
According to Le Chatelier's principle, any disturbance caused in an equilibrium reaction will tend to shift the equilibrium in a direction away from the disturbance.
For example, 
Hence, expression for equilibrium constant will be as follows.
![K_{eq} = \frac{[Ca^{2+}][HCO^{-}_{3}]^{2}}{[CO_{2}][H_{2}O]}](https://tex.z-dn.net/?f=K_%7Beq%7D%20%3D%20%5Cfrac%7B%5BCa%5E%7B2%2B%7D%5D%5BHCO%5E%7B-%7D_%7B3%7D%5D%5E%7B2%7D%7D%7B%5BCO_%7B2%7D%5D%5BH_%7B2%7DO%5D%7D)
Since, the concentration for a solid substance is considered as 1 or unity. Therefore, adding or removing a solid will not affect the equilibrium.
Thus, we can conclude that according to Le Châtelier’s Principle, the amount of solid reactant or product present does not have an impact on the equilibrium because the solid does not appear in the equilibrium constant, so adding or removing solid has no effect.
The Atomic Number and Atomic Mass of ²⁸Si₁₄ are 14 and 28 respectively.
Atomic Number:
Atomic Number of Element is the Number of Protons contained by the Element. So, there are 14 Protons in ²⁸Si₁₄.
Atomic Mass:
Atomic Mass of Element is the total number of Protons and Neutrons present in the Nucleus of that element.
So,
Atomic Mass = # of Protons + # of Neutrons
As the Atomic mass of ²⁸Si₁₄ is 28 and it has 14 protons, So # of Neutrons are calculated as,
# of Neutrons = Atomic Mass - # of Protons
# of Neutrons = 28 - 14
# of Neutrons = 14
Result:
In ²⁸Si₁₄ Number of Neutrons are 14, Number of Protons are 14.
Z = 14 , n = 14
Answer:
Explanation: In the previous section we listed four characteristics of radioactivity and nuclear decay that form the basis for the use of radioisotopes in the health and biological sciences. A fifth characteristic of nuclear reactions is that they release enormous amounts of energy. The first nuclear reactor to achieve controlled nuclear disintegration was built in the early 1940s by Enrico Fermi and his colleagues at the University of Chicago. Since that time, a great deal of effort and expense has gone into developing nuclear reactors as a source of energy. The nuclear reactions presently used or studied by the nuclear power industry fall into two categories: fission reactions and fusion reactions
