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lord [1]
3 years ago
9

SF3 VSEPR model (Help Please)

Chemistry
1 answer:
Dmitry_Shevchenko [17]3 years ago
4 0

Answer

You did not add the image please make a new question or edit this question.

Explanation:

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The observation that 20g of hydrogen gas always combines with 160g of oxygen gas to form 180g of water, even when there is more
mash [69]

Answer:

The answer is most likely A. Definite proportions

Explanation:

The Law of Definite proportions states that a given chemical compound always contains its component elements in fixed ratio (by mass) and does not depend on its source and method of preparation.

3 0
3 years ago
Examine the equation.
Alisiya [41]

Explanation:

The reaction expression is given as;

                 2H₂_{g}   +  O₂_{g}   →   2H₂O_{l}

From the balance reaction expression:

 2 mole of hydrogen gas combines with 1 mole of oxygen gas on the reactant side;

This produces 2 mole of water on the product side of the expression.

The product is in liquid form.

 This reaction is a synthesis reaction because a single product is formed from two reactants.

5 0
3 years ago
What is the oxidation number of sulfur in H2SO3?<br> a. +3<br> b. +1<br> c. +2<br> d. +4
Alla [95]
We need to keep in mind that the compound is neutral.

H2SO3
2(+1)+S+3(-2)=0 (since its neutral)
2+S-6=0
S-4=0
S=4

Therefore the oxidation number for sulfur is +4.
3 0
3 years ago
Read 2 more answers
I’m trying to figure out how to convert 6 moles KCL to particles.
I am Lyosha [343]

Answer:

How many moles KCl in 1 grams? The answer is 0.013413582325

1 mole is equal to 1 moles KCl, or 74.5513 grams.

447.3078 is the answer

Explanation:

<em>~Cornasha_Weeb</em>

7 0
3 years ago
A critical reaction in the production of energy in biological systems is the hydrolysis of adenosine triphosphate (ATP) to adeno
Archy [21]

Answer:

ΔG° of reaction =  -47.3 x 10^{3} J/mol      

Explanation:

As we can see, we have been a particular reaction and Energy values as well.

ΔG° of reaction = -30.5 kJ/mol

Temperature = 37°C.

And we have to calculat the ΔG° of reaction in the biological cell which contains ATP, ADP and HPO4-2:

The first step is to calculate the equilibrium constant for the reaction:

Equilibrium Constant K = \frac{[HPO4-2] x [ADP]}{ATP}

And we have values given for these quantities in the biological cell:

[HP04-2] = 2.1 x 10^{-3} M

[ATP] = 1.2 x 10^{-2} M

[ADP] = 8.4 x 10^{-3} M

Let's plug in these values in the above equation for equilibrium constant:

K = \frac{[2.1x10^{-3}] x [8.4x10^{-3}] }{[1.2 x 10^{-2}] }

K = 1.47 x 10^{-3} M

Now, we have to calculate the ΔG° of reaction for the biological cell:

But first we have to convert the temperature in Kelvin scale.

Temp = 37°C

Temp = 37 + 273

Temp = 310 K

ΔG° of reaction = (-30.5 10^{3}) + (8.314)x (310K)xln(0.00147)

Where 8.314 = value of Gas Constant

ΔG° of reaction = (-30.5 x 10^{3}) + (-16810.68)

ΔG° of reaction = -47.3 x 10^{3} J/mol

5 0
3 years ago
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