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2 years ago

6

What type of atoms will end up with a negative charge?

2 answers:

Semmy [17]2 years ago

8 0

Hi SMA16,

Your Question:

What type of atoms will end up with a negative charge?

Answer:

An <u>electron</u> will end up with a negative charge!

Hope This Helps!

sashaice [31]2 years ago

6 0

An atom is composed by 3 subatomic particles, which are neutrons, electrons and protons.

Neutrons: neutre charge

Electrons: negative charge

Protons: positive charge

Answer:

$\boxed{\bf~Electrons}$

Hope it helped,

BioTeacher101

You might be interested in

How to<br> find the number of proton and neutron

VladimirAG [237]

go to periodic table

look for the element you want

find the atomic number on the top right hand side of the element

atomic number = equal to number of proton.

find atomic mass bottom right hand side of the element

atomic mass - atomic number = neutron

i hope this will help

Na atomic number 11 and mass number 23

protons 11

neutron =23-11=12

7 0

2 years ago

Consider the following genotype Yy Ss Hh

Ilya [14]

From: Yy Ss Hh 8 different gametes can be formed

5 Eye Color Genes = 243 genotypes
10 Eye Color Genes= 59049 genotypes
20 Eye Color Genes= 3,486,784,401 genotypes

This is further explained below.

<h3>What is a gamete?</h3>

Generally, Gametes are the cells of an organism that are responsible for reproduction. In certain contexts, they are also referred to as egg cells and sperm cells.

The popular word for female gametes is ova, whereas the common name for male gametes is sperm. Ovum and egg cells are other frequent names for female gametes.

Gametes are instances of haploid cells since they only contain a single copy of each chromosome. Haploid cells are described as having only one copy of each chromosome.

In conclusion, For 5 Eye Color Genes

3^n is implored hence

3^5=243 genotypes

Repeating said pattern e have

10 Eye Color Genes= 59049 genotypes
20 Eye Color Genes= 3,486,784,401 genotypes

Read more about gamete

brainly.com/question/2569962

#SPJ1

CQ

4. Consider the following genotype: Yy Ss Hh. We have now added the gene for height: Tall (H) or Short (h).

a. How many different gamete combinations can be produced?

b. Many traits (phenotypes), like eye color, are controlled by multiple genes. If eye color were controlled by the number of genes indicated below, how many possible genotype combinations would there be in the following scenarios?

a. 5 Eye Color Genes:

b. 10 Eye Color Genes:

c. 20 Eye Color Genes:

6 0

10 months ago

Carbon-14 (14C) dating assumes that the carbon dioxide on the Earth today has the same radioactive content as it did centuries a

Nataly [62]

<u>Answer:</u> The tree was burned 16846.4 years ago to make the ancient charcoal

<u>Explanation:</u>

The equation used to calculate rate constant from given half life for first order kinetics:

$t_{1/2}=\frac{0.693}{k}$

where,

$t_{1/2}$ = half life of the reaction = 5715 years

Putting values in above equation, we get:

$k=\frac{0.693}{5715yrs}=1.21\times 10^{-4}yrs^{-1}$

Rate law expression for first order kinetics is given by the equation:

$k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}$

where,

k = rate constant = $1.21\times 10^{-4}yr^{-1}$

t = time taken for decay process = ? yr

$[A_o]$ = initial amount of the sample = 100 grams

[A] = amount left after decay process = 13 grams

Putting values in above equation, we get:

$1.21\times 10^{-4}=\frac{2.303}{t}\log\frac{100}{13}\\\\t=16864.4yrs$

Hence, the tree was burned 16846.4 years ago to make the ancient charcoal

8 0

2 years ago

We want to calculate the concentrations of all species in a 0.58 M Na 2 SO 3 (sodium sulfite) solution. The ionization constants

NeX [460]

Explanation:

Reaction equation is as follows.

$Na_{2}SO_{3}(s) \rightarrow 2Na^{+}(aq) + SO^{2-}_{3}(aq)$

Here, 1 mole of $Na_{2}SO_{3}$ produces 2 moles of cations.

$[Na^{+}] = 2[Na_{2}SO_{3}] = 2 \times 0.58$

= 1.16 M

$[SO^{2-}_{3}] = [Na_{2}SO_{3}]$ = 0.58 M

The sulphite anion will act as a base and react with $H_{2}O$ to form $HSO^{-}_{3}$ and $OH^{-}$ .

As, $K_{b} = \frac{K_{w}}{K_{a_{2}}}$

= $\frac{10^{-14}}{6.3 \times 10^{-8}}$

= $1.59 \times 10^{-7}$

According to the ICE table for the given reaction,

$SO^{2-}_{3} + H_{2}O \rightleftharpoons HSO^{-}_{3} + OH^{-}$

Initial: 0.58 0 0

Change: -x +x +x

Equilibrium: 0.58 - x x x

So,

$K_{b} = \frac{[HSO^{-}_{3}][OH^{-}]}{[SO^{2-}_{3}]}$

$1.59 \times 10^{-7} = \frac{x^{2}}{0.58 - x}$

$x^{2} = 1.59 \times 10^{-7} \times (0.58 - x)$

x = 0.0003 M

So, x = $[HSO^{-}_{3}] = [OH^{-}]$ = 0.0003 M

$[SO^{2-}_{3}]$ = 0.58 - 0.0003

= 0.579 M

Now, we will use $[HSO^{-}_{3}]$ = 0.0003 M

The reaction will be as follows.

$HSO^{2-}_{3} + H_{2}O \rightleftharpoons H_{2}SO_{3} + OH^{-}$

Initial: 0.0003

Equilibrium: 0.0003 - x x x

$K_{b} = \frac{x^{2}}{0.0003 - x}$

$K_{b} = \frac{K_{w}}{K_{a_{1}}}$

= $\frac{10^{-14}}{1.4 \times 10^{-2}}$

= $7.14 \times 10^{-13}$

Therefore, $7.14 \times 10^{-13} = \frac{x^{2}}{0.0003 - x}$

As, x <<<< 0.0003. So, we can neglect x.

Therefore, $x^{2} = 7.14 \times 10^{-13} \times 0.0003$

= $0.00214 \times 10^{-13}$

x = $0.0146 \times 10^{-6}$

x = $[OH^{-}] = [H_{2}SO_{3}]$ = $1.46 \times 10^{-8}$

$[H^{+}] = \frac{10^{-14}}{[OH^{-}]}$

= $\frac{10^{-14}}{0.0003}$

= $3.33 \times 10^{-11}$ M

Thus, we can conclude that the concentration of spectator ion is $3.33 \times 10^{-11}$ M.

5 0

2 years ago

What are 3 household substances that contain acids and say why are they useful

Nonamiya [84]

Answer:

battery. you use it for your remotes. vinegar. you use vinegar for cooking of cleaning. nail polish remover. you use this for removing nail polish

6 0

2 years ago