Answer is 0.1565417867........
Answer:
The solution will not form a precipitate.
Explanation:
The Ksp of PbI₂ is:
PbI₂(s) ⇄ 2I⁻(aq) + Pb²⁺(aq)
Ksp = 1.40x10⁻⁸ = [I⁻]²[Pb²⁺] <em>Concentrations in equilibrium</em>
When 328mL of 0.00345M NaI(aq) is combined with 703mL of 0.00802M Pb(NO₃)₂. Molar concentration of I⁻ and Pb²⁺ are:
[I⁻] = 0.00345M × (328mL / (328mL+703mL) =<em> 1.098x10⁻³M</em>
[Pb²⁺] = 0.00802M × (703mL / (328mL+703mL) =<em> 5.469x10⁻³M</em>
<em />
Q = [I⁻]²[Pb²⁺] <em>Concentrations not necessary in equilibrium</em>
If Q = Ksp, the solution is saturated, Q > Ksp, the solution will form a precipitate, if Q < Ksp, the solution is not saturated.
Replacing:
Q = [1.098x10⁻³M]²[5.469x10⁻³M] = 6.59x10⁻⁹
As Q < Ksp, the solution is not saturated and <em>will not form a precipitate</em>.
Answer:
The Density of the cube of metal is 2.675g/mL or 2675kg/mL.
Explanation:
Given the following data;
Mass of metal = 1.45kg to gram (g) = 1.45 × 1000 = 1450g
Volume of the cube of metal = 542mL
Density = ?
Density can be defined as mass all over the volume of an object.
Simply stated, density is mass per unit volume of an object.
Mathematically, density is given by the equation;
Substituting into the equation, we have;
<em>Density = 2.675g/mL</em>
In kilograms, the density is 2.675 x 1000 = 2675kg/mL.
Answer:
The answer to your question is below: 8 electron in its outer most shell.
Explanation:
Argon like noble gases are stable elements that means that they do not react with other elements. They have eight electrons in their outermost shell; Elements are stable when they reach 8 electronsin their outer most shell, some elements reach 8 electrons receiving from others (nonmetals) and others donate electrons ( metals).
Answer:
D. 0.60 L.
Explanation:
- For the acid-base neutralization, we have the role:
The no. of millimoles of acid is equal to that of the base at the neutralization.
<em>∴ (XMV) NaOH = (XMV) H₂SO₄.</em>
X is the no. of reproducible H⁺ (for acid) or OH⁻ (for base),
M is the molarity.
V is the volume.
X = 1, M = 4.0 M, V = ??? L.
X = 2, M = 4.0 M, V = 0.3 L.
∴ V of NaOH = (XMV) H₂SO₄/(XM) NaOH = (2)(4.0 M)(0.3 L)/(1)(4.0 M) = 0.6 L.
<em>So, the right choice is: D. 0.60 L.</em>
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