How much calcium hydroxide in grams is needed to produce 1.5 l of a 0.25m solution?

1 answer:

6 0

The mass ca(Oh)2 needed to produce 1.5 l of 0.25 solution is calculated as follows
find moles

=moles = molarity x volume

moles is therefore = 1.5 x 0.25 = 0.375 moles

mass = moles x molar mass
0.375mol x 74.09 g/mol = 27.78 grams

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