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kotegsom [21]
3 years ago
14

How much calcium hydroxide in grams is needed to produce 1.5 l of a 0.25m solution?

Chemistry
1 answer:
Vesna [10]3 years ago
6 0
The  mass    ca(Oh)2  needed  to  produce  1.5 l  of  0.25 solution  is  calculated  as follows
find  moles
 
=moles   = molarity   x  volume

moles is therefore =   1.5  x 0.25  =  0.375  moles

mass  =  moles  x  molar  mass
0.375mol  x  74.09 g/mol  =  27.78  grams
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Answer:

pH = 4.27. Porcentaje de disociación: 0.03%

Explanation:

El pH de un ácido débil, HX, se obtiene haciendo uso de su equilibrio:

HX(aq) ⇄ H⁺(aq) + X⁻(aq)

Donde la constante de equilibrio, Ka, es

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Como los iones H⁺ y X⁻ vienen del mismo equilibrio podemos decir:

[H⁺] = [X⁻]

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Reemplazando es Ka:

1.65x10⁻⁸ = [H⁺] [H⁺] / [0.1732M]

2.858x10⁻⁹ = [H⁺]²

5.35x10⁻⁵M = [H⁺]

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El porcentaje de disociacion es [X⁻] / [HX] inicial * 100

Reemplazando

5.35x10⁻⁵M / 0.1732M * 100

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