The quadratic equation that models the height of the rocket after t seconds is:
s(t) = -4.9t² + 39.2t.
<h3>What is the quadratic function for a projectile's height?</h3>
Considering the height in meters, the equation is given by:
s(t) = -4.9t² + v(0)t + h(0)
In which:
- v(0) is the initial velocity, in m/s.
- h(0) is the initial height, in m.
In this problem, we have that v(0) = 39.2, h(0) = 0, hence the equation is:
s(t) = -4.9t² + 39.2t.
More can be learned about quadratic functions at brainly.com/question/24737967
#SPJ1
24.8 cm ÷ 175= 0.141... or 0.14 cm.
The answer is 0.14 cm
Tolerance = 1% = 0.01 on a shaft of 15 in
Tolerance in inches = 15 x 0.01 =0.15 in
Since it' s a tolerance the acceptable error is either +0.15in or -0.15 in
Circumference of a circle: 2 * Pi * R
1. Calculate radius from diameter.
Radius = Diameter/2
Radius = 15/2
Radius = 7.5cm
Formula to calculate the circumference:
2 * Pi * R
= 2 * Pi * 7.5
= 15 * Pi
= About 47.10 cm in terms of Pi.
So, in conclusion, the circumference if this circle is about: 47.10cm.
