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Pani-rosa [81]
4 years ago
6

Why is a capacity of 25 fluid ounces more than a capacity of 3 cups?

Mathematics
2 answers:
garri49 [273]4 years ago
6 0

Answer:

A cup is 8 ounces. so your answer would be C. Because when you divide 25 by 8, the result is greater than 3.

Step-by-step explanation:

yessir

mixas84 [53]4 years ago
5 0
A cup is 8 ounces. so your answer would be C. Because <span>when you divide 25 by 8, the result is greater than 3.</span>
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Find x and y if x=2y-8 and y=9x-7
german

Answer:

x = (22/17), y= (79/17)

Step-by-step explanation:

Just substitute x = 2y - 8 into y = 9x - 7 and solve.

6 0
4 years ago
PLS HELP ME ASAP WITH NUMBER 37
Reil [10]
A) The equations are shown on the attached graph.
x = juice box cost
y = water bottle cost

B) Kara's proposed solution satisfies the first equation, but not the second one.

C) The solution is shown on the attached graph.

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As a bonus, you get a graph for the other problem you posted. Please note this graph has some issues. Wherever there's a solid line ⌝ or ⌞ the actual shape of the graph should be the opposite one of these.

5 0
3 years ago
The cost of two mopeds is the same as the cost of seven bicycles. the cost of one bicycle is $152. therefore, the cost of one mo
DanielleElmas [232]
7 bicycles dived by two mopeds = 3.5
$152 x 3.5 = $532

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7 0
3 years ago
What is 3/2=9/10k im having troble lots rly
tigry1 [53]

Answer:

k=  5 over 3  =1.667

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    (3)/(2)-((9)/(10)*k)=0

simplify 9/10

 3      9

 — -  (—— • k)  = 0  

 2     10

simplify 3/2

 3    9k

 — -  ——  = 0  

 2    10

   Find the Least Common Multiple

     The left denominator is :       2  

     The right denominator is :       10

Least Common Multiple:

     10

Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M  

   Denote the Left Multiplier by  Left_M  

   Denote the Right Multiplier by  Right_M  

   Denote the Left Deniminator by  L_Deno  

   Denote the Right Multiplier by  R_Deno  

  Left_M = L.C.M / L_Deno = 5

  Right_M = L.C.M / R_Deno = 1

Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      3 • 5

  ——————————————————  =   —————

        L.C.M              10  

  R. Mult. • R. Num.      9k

  ——————————————————  =   ——

        L.C.M             10

Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

3 • 5 - (9k)     15 - 9k

————————————  =  ———————

     10            10  

Pull out like factors :

  15 - 9k  =   -3 • (3k - 5)

-3 • (3k - 5)

 —————————————  = 0  

      10      

When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 -3•(3k-5)

 ————————— • 10 = 0 • 10

    10    

Now, on the left hand side, the  10  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  -3  •  (3k-5)  = 0

Solve :    -3   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solve  :    3k-5 = 0  

Add  5  to both sides of the equation :  

                     3k = 5

Divide both sides of the equation by 3:

                    k = 5/3 = 1.667

one solution was found

k = 5/3 = 1.667

hope it helps sry its so long

7 0
4 years ago
Will is w years old.
Furkat [3]
Ben = e
Jan = 2e

2e = w  (not will)

8 0
4 years ago
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