What is the answer to 4 x 3+2n

Pyramid A has a triangular base where each side measures 4 units and a volume of 36 cubic units. Pyramid B has the same height,

omeli [17]

Answer:

The volume of pyramid B is 81 cubic units

Step-by-step explanation:

Given

Pyramid A

$s = 4$ -- base sides

$V = 36$ -- Volume

Pyramid B

$s = 6$ --- base sides

Required

Determine the volume of pyramid B [Missing from the question]

From the question, we understand that both pyramids are equilateral triangular pyramids.

The volume is calculated as:

$V = \frac{1}{3} * B * h$

Where B represents the area of the base equilateral triangle, and it is calculated as:

$B = \frac{1}{2} * s^2 * sin(60)$

Where s represents the side lengths

First, we calculate the height of pyramid A

For Pyramid A, the base area is:

$B = \frac{1}{2} * s^2 * sin(60)$

$B = \frac{1}{2} * 4^2 * \frac{\sqrt 3}{2}$

$B = \frac{1}{2} * 16 * \frac{\sqrt 3}{2}$

$B = 4\sqrt 3$

The height is calculated from:

$V = \frac{1}{3} * B * h$

This gives:

$36 = \frac{1}{3} * 4\sqrt 3 * h$

Make h the subject

$h = \frac{3 * 36}{4\sqrt 3}$

$h = \frac{3 * 9}{\sqrt 3}$

$h = \frac{27}{\sqrt 3}$

To calculate the volume of pyramid B, we make use of:

$V = \frac{1}{3} * B * h$

Since the heights of both pyramids are the same, we can make use of:

$h = \frac{27}{\sqrt 3}$

The base area B, is then calculated as:

$B = \frac{1}{2} * s^2 * sin(60)$

Where

$s = 6$

So:

$B = \frac{1}{2} * 6^2 * sin(60)$

$B = \frac{1}{2} * 36 * \frac{\sqrt 3}{2}$

$B = 9\sqrt 3$

So:

$V = \frac{1}{3} * B * h$

Where

$B = 9\sqrt 3$ and $h = \frac{27}{\sqrt 3}$

$V = \frac{1}{3} * 9\sqrt 3 * \frac{27}{\sqrt 3}$

$V = \frac{1}{3} * 9 * 27$

$V = 81$

6 0

3 years ago

Read 2 more answers

You shouldn't get this question wrong, right?

uranmaximum [27]

Answer:

You have THREE OR 3 APPLES

4 0

2 years ago

Read 2 more answers

Can someone please help me i don’t understand it

forsale [732]

Answer:

d= bv + r

Treat it like you would a normal equation. Multiply by b and add r to isolate d.

5 0

3 years ago

Help me with this problem I will give brainliest

Inga [223]

Answer:

x=3

Step-by-step explanation:

7 0

3 years ago

What is the interquartile range of the data ? 0,2,4,0,2,3,8,6

Alexeev081 [22]

(arrange the data set from least to greatest)

0, 0, 2, 2, 3, 4, 6, 8

(find the median: *the middle number*)

Median: 2.5

Lower quartile: 1

Upper quartile: 5

Interquartile range : upper quartile - lower quartile = answer

Interquartile range: 5 - 1 = 4

So the IQR or interquartile for the following data set is 4.

6 0

3 years ago