Answer:
AB = ![\left[\begin{array}{ccc}-3&4&6\\-6&3&5\\5&0&-4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%264%266%5C%5C-6%263%265%5C%5C5%260%26-4%5Cend%7Barray%7D%5Cright%5D)
Each column of AB is written as a linear combination of columns of Matrix A in the explanation below.
Step-by-step explanation:
A = ![\left[\begin{array}{ccc}-2&2&1\\-3&1&1\\2&0&-1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%262%261%5C%5C-3%261%261%5C%5C2%260%26-1%5Cend%7Barray%7D%5Cright%5D)
B= ![\left[\begin{array}{ccc}2&-1&0\\1&2&1\\-1&-2&4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%26-1%260%5C%5C1%262%261%5C%5C-1%26-2%264%5Cend%7Barray%7D%5Cright%5D)
We need to write each column of AB as a linear combination of the columns of A so we will multiply each column of A with each column element of B to get the column of AB. So,
AB Column 1 = 2 * ![\left[\begin{array}{ccc}-2\\-3\\2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%5C%5C-3%5C%5C2%5Cend%7Barray%7D%5Cright%5D)
+ 1 ![\left[\begin{array}{ccc}2\\1\\0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%5C%5C1%5C%5C0%5Cend%7Barray%7D%5Cright%5D)
+ (-1) ![\left[\begin{array}{ccc}1\\1\\-1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%5C%5C1%5C%5C-1%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}-3\\-6\\5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%5C%5C-6%5C%5C5%5Cend%7Barray%7D%5Cright%5D)
AB Column 2 = (-1) + 2 + (-2) = ![\left[\begin{array}{ccc}4\\3\\0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%5C%5C3%5C%5C0%5Cend%7Barray%7D%5Cright%5D)
AB Column 3 = (0) + (1) + 4 = ![\left[\begin{array}{ccc}6\\5\\-4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%5C%5C5%5C%5C-4%5Cend%7Barray%7D%5Cright%5D)
Finally, we can combine all three columns of AB to form the 3x3 matrix AB.
AB =
Answer:
a
Step-by-step explanation:
i did this test and question beforer si know what it iso
Answer:
A = 187.5L - L^2
So,
g(l) = 187.5l - l^2
Step-by-step explanation:
The perimeter of a rectangle is given by:
P = 2(L + B)
Where P = perimeter
L = Length
B = Width
Making B the subject of formula, we have;
B = P/2 - L ......1
The area of a rectangle is:
A = L × B ........2
Substituting equation 1 to 2.
A = L × (P/2 - L)
A = LP/2 - L^2 .......3
Given that the perimeter P = 375 inches
A = L(375)/2 - L^2
A = 187.5L - L^2
So,
g(l) = 187.5l - l^2
Answer:
12
Step-by-step explanation:
12^2 is the greatest number that is closest to 148. then there is 4 as the smaller number 12-4=8
144+4=148
<u>Given</u><u> info</u><u>:</u><u>-</u> In triangle (∆)ABC , in which ∠A = 2x, ∠B = x+15° and ∠C = 2x + 10°. Then find the value of x , also find the measure of each angles of a triangle.
<u>Explanation</u><u>:</u><u>-</u>
Let the angles be 2x, x+15 and 2x+10 respectively.
∵ Sum of the three angles of a triangle is 180°
∴ ∠A + ∠B + ∠C = 180° [Sum of ∠s of a ∆=180°]
→2x + x+15 + 2x+10 = 180°
→ 2x + x + 2x + 15 + 10 = 180°
→ 3x + 2x + 15 + 10 = 180°
→ 5x + 15 + 10 = 180°
→ 5x + 25 = 180°
→ 5x = 180°-25
→ 5x = 155°
→ x = 155°÷5 = 155/5 = 31.
Now, finding the measure of each angles of a ∆ABC by putting the original value of “x”.
∴ ∠A = 2x = 2(31) = 62°
∠B = x+15 = 31 + 15 = 46°
∠C = 2x + 10 = 2(31) + 10 = 62 + 10 = 72°.
