Answer:
The critical value is T = 1.895.
The 90% confidence interval for the mean repair cost for the washers is between $48.159 and $72.761
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 8 - 1 = 6
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 6 degrees of freedom(y-axis) and a confidence level of 
. So we have T = 1.895, which is the critical value.
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 60.46 - 12.301 = $48.159
The upper end of the interval is the sample mean added to M. So it is 60.46 + 12.301 = $72.761
The 90% confidence interval for the mean repair cost for the washers is between $48.159 and $72.761
Since the triangles are similar, all sides are proportional by the same scale factor.
The relationship between the bases 32 and 8 is 4 (32/8 = 4). This means that the smaller triangle need to be multiplied by a scale factor 4 to result in the bigger triangle.
This means that 4x + 12 is 4 times greater than 15.
The equation to solve for x can be written as:
4x + 12 = 4*15
Now just solve for x as u normally would
4x + 12 = 60
(Subtract twelve from both sides)
4x = 48
(Divide both sides by 4 to isolate x)
x = 12
I hope this somewhat helped :)
Was my explanation clear enough?
Step-by-step explanation:
First, let's distribute the 
variable to each term in the first parenthesis:
Next, let's distribute the variable to each term in the second parenthesis:
Next, let's group like terms together:
Finally, let's add or subtract like terms to get the result:
Answer:
A. True
Step-by-step explanation:
......................................................................................
Step-by-step explanation:
a.3.4cm
b.23000l
c.0.016g
d.3000m
e.2000mg
