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3 years ago

Which pair of terms below correctly completes the following sentence?

Mathematics

2 answers:

AysviL [449]3 years ago

7 0

For a given function an asymptote is a value for which the denominator of the function becomes zero.

And so the function becomes undefined.

Also if the denominator of any fraction is zero, the value of the fraction goes on to become infinity or very large.

A function has vertical asymptotes at x-values for which it is <u>Undefined</u> and near which the function's values become very <u>Large</u> positive or negative numbers.

Option C) is the right answer.

mr_godi [17]3 years ago

6 0

The answer is c undefined;large

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What if Jake has two shirts, five pairs of pants and four sweaters? How many

Stolb23 [73]

Answer:

Step-by-step explanation:

There are 5 pants 2 shirts and 4 sweaters which makes 6 together, paired up makes 5 outfits and one extra sweater or shirt.

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3 years ago

The quadratic formula gives which roots for the equation 2x^2 + x - 6 = 0?

Jet001 [13]

Answer:

The roots are $x = (\frac{3}{2}, -2)$ , which is given by option C.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}$

$\Delta = b^{2} - 4ac$

In this question, we have that:

$2x^2 + x - 6 = 0$

Which is a quadratic equation with $a = 2, b = 1, c = -6$ . So

$\Delta = 1^{2} - 4*2(-6) = 1 + 48 = 49$

$x_{1} = \frac{-1 + \sqrt{49}}{2*2} = \frac{6}{4} = \frac{3}{2}$

$x_{2} = \frac{-1 - \sqrt{49}}{2*2} = \frac{-8}{4} = -2$

So the roots are $x = (\frac{3}{2}, -2)$ , which is given by option C.

3 0

3 years ago

The size of a television screen is given as the length of diagonal. For example, a 29 inch screen is 29 inches from the lower le

Valentin [98]

Answer:

Step-by-step explanation:

6 0

3 years ago

Please help! Due very soon! help ASAP!!!

Vanyuwa [196]

B and C are correct.

8 0

2 years ago

Read 2 more answers

Part A. Let $f(x) = x^4-3x^2 + 2$ and $g(x) = 2x^4 - 6x^2 + 2x -1$. Let $a$ be a constant. What is the largest possible degree o

Varvara68 [4.7K]

Answer:

A. 4

B. 1

Step-by-step explanation:

The degree of a one-variable polynomial is the largest exponent of the variable.

For f(x) = x^4 -3x^2 +2 and g(x) = 2x^4 -6x^2 +2x -1, the sum f(x) +a·g(x) will be ...

(x^4 -3x^2 +2) +a(2x^4 -6x^2 +2x -1)

= (1 +2a)x^4 +(-3-6a)x^2 +2ax -a

The term with the largest exponent is (1 +2a)x^4, which has degree 4. This term will be non-zero for a ≠ -1/2.

The largest possible degree of f+ag is 4.

The polynomial sum is ...

f+bg = (1 +2b)x^4 +(-3-6b)x^2 +2bx -b

When b = -1/2, the first two terms disappear and the sum becomes ...

f+bg = -x +1/2 . . . . . . a polynomial of degree 1

The smallest possible degree of f+bg is 1.

5 0

2 years ago