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erastovalidia [21]
3 years ago
8

which properties are present in a table that represents an exponential function in the form y=b^x when b>1​

Mathematics
1 answer:
vladimir1956 [14]3 years ago
3 0

Answer:

The function has the property of exponential growth function.

Step-by-step explanation:

The exponential function is given by y = b^{x}, where b > 1.

Now, for x = 0, we get y = 1,

For x = 1, we get y = b

For, x = 2, we get y = b²

And so on.

Now, as b > 1, so, b² > b > 1 and the values of y are increasing as the value of x increases.

Therefore, the function has the property of exponential growth function.

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When using substitution to solve this system of equations, what is the result of the first step?
Allushta [10]

Answer:

The method of solving "by substitution" works by solving one of the equations (you choose which one) for one of the variables (you choose which one), and then plugging this back into the other equation, "substituting" for the chosen variable and solving for the other. Then you back-solve for the first variable.

Step-by-step explanation:

Hope this helps you

3 0
2 years ago
Read 2 more answers
Can someone do this fast ? I need it for tomorrow
gregori [183]

Answer:

Step-by-step explanation:

hg(x) means you multiply h(x) times g(x) and then we will set it equal to 3x^2+x-1.

hg(x) = x^2(x+2) which simplifies to

x^3+2x^2. Now set that equal to 3x^2+x-1:

x^3+2x^2=3x^2+x-1 and get everything on the same side and factor:

x^3-x^2-x+1=0. Factor by grouping:

(x^3-x^2)-(x+1)=0 and factor out what's common in each set of ( ):

x^2(x-1)-1(x-1)=0 which factors out to

(x^2-1)(x-1)=0. But x^2-1 factors somoe to:

(x + 1)(x - 1)(x - 1) = 0 So the solutions for this are

x = -1, 1

7 0
2 years ago
P(x)= 2x^3-x^2+5 is divided by x+2. Choose the correct option from drop menu.
koban [17]

The answer depends on what type of division it is. Synthetic?

7 0
2 years ago
A physical fitness association is including the mile run in its secondary-school fitness test. The time for this event for boys
Luba_88 [7]

Answer:

z=-1.28

And if we solve for a we got

a=470 -1.28*60=393.2

So the value of height that separates the bottom 10% (Fastest 10%) of data from the top 90% is 393.2.

so if the time is 393.2 or lower a boy would earn a certificate of recognition from the fitness association

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the time for this event of a population, and for this case we know the distribution for X is given by:

X \sim N(470,60)  

Where \mu=470 and \sigma=60

NOTE: For this case the fastest 10% is on the lower tail of the distribution

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.9   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.1 of the area on the left and 0.9 of the area on the right it's z=-1.28. On this case P(Z<-1.28)=0.1 and P(z>-1.28)=0.9

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=-1.28

And if we solve for a we got

a=470 -1.28*60=393.2

So the value of height that separates the bottom 10% (Fastest 10%) of data from the top 90% is 393.2.

so if the time is 393.2 or lower a boy would  earn a certificate of recognition from the fitness association

4 0
3 years ago
The sum of three numbers is 129. The third number is 4 times the first. The first number is 9 less than the second. What are the
Rasek [7]
X=23, Y=14, & Z=92 is your answer
8 0
2 years ago
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