Which statement holds true for a skewed histogram showing a distribution of the weights of students in a class?
2 answers:
Answer: A). The number of weights on the right side of the mode is equal to the number of weights on the left.
Step-by-step explanation:
A is it and that might help
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Answer:
Hope this helps
Step-by-step explanation:
4(3+14c−12d)
=(4)(3+14c+−12d)
=(4)(3)+(4)(14c)+(4)(−12d)
=12+c−2d
=c−2d+12
It is not specified how much she was saving before...
If 0 than it is D 70/543
Y=(-1/6)x+5
m=(y2-y1)/(x2-x1)
m=(3-6)/(12-(-6))
m=(-3)/(18)
m=-1/6
y=mx+b
y=(-1/6)x+b
6=(-1/6)(-6)+b
6=1+b
b=5
y=(-1/6)x+5
The answer you want will be 10.
Hope it helps!!